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3 years ago

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Given the equation: HCI + Na2SO4 ---> NaCl + H2SO4 Hint: you should balance the equation If you start with 2.0 g of HCl (hydr

ochloric acid), how many grams of H2SO4 (sulfuric acid) will be produced?

1 answer:

Rasek [7]3 years ago

3 0

Answer:

approx 2.45g

Explanation:

2HCl + Na2SO4 → 2NaCl + H2SO4

2 : 1 : 2 : 1

0.05 0.025 (moles)

⇒ mH2SO4 = 0.025 × 98 = 2.45 g

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N2 (g) + 2O2(g) = 2NO2 (g) ΔH = 66.4 kJ 2NO (g) + O2 (g) = 2NO2 (g) ΔH = -114.2 kJ the enthalpy of the reaction of the nitrogen

RSB [31]

Answer:

ΔH = 180.6 kJ

Explanation:

Given that:

N2 (g) + 2O2(g) = 2NO2 (g) ΔH = 66.4 kJ

<u>2NO (g) + O2 (g) = 2NO2 (g) ΔH = -114.2 kJ </u>

N2 (g) + O2 (g) = 2NO (g) ΔH = ????

The subtraction of both equations would yield the unknown ΔH , therefore:

ΔH = 66.4 - ( - 114.2 kJ)

ΔH = 180.6 kJ

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Yuri [45]

Answer : The correct option is, (e) eg = trigonal planar, mg = trigonal planar

Explanation :

Formula used :

$\text{Number of electron pair}=\frac{1}{2}[V+N-C+A]$

where,

V = number of valence electrons present in central atom

N = number of monovalent atoms bonded to central atom

C = charge of cation

A = charge of anion

The given molecule is, $CH_3^+$

$\text{Number of electron pair}=\frac{1}{2}\times [4+3-1]=3$

That means,

Bond pair = 3

Lone pair = 0

The number of electron pair are 3 that means the hybridization will be $sp^2$ and the electronic geometry of the molecule will be trigonal planar.

Hence, the electron geometry (eg) and molecular geometry (mg) of $CH_3^+$ is, trigonal planar and trigonal planar respectively.

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