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Eddi Din [679]
3 years ago
7

A student submits the following work on the mass number, but he has made a few mistakes. Select all of his mistakes.

Chemistry
2 answers:
MatroZZZ [7]3 years ago
8 0

Answer:

1. <u>Calculating the mass number for an atom requires that we know the atomic number and the number of protons in the atom's nucleus.</u>

2. <u>The mass number then gives us the average weight of atoms of a given element.</u>

3. <u>However, as long as the number of protons equals the number of neutrons, the values balance out and we always obtain a whole number for the mass number.</u>

Explanation:

MatroZZZ [7]3 years ago
4 0

Do you know the answer?

:)

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Why are alkali metals so reactive?
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<em>Alkali metals are among the most reactive metals. This is due in <u>part to their larger atomic radii and low ionization energies.</u> They tend to donate their electrons in reactions and have an oxidation state of +1. ... All these characteristics can be attributed to these elements' large atomic radii and weak metallic bonding.</em>

Explanation:

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8 0
2 years ago
What does this do to the electrons outside the nucleus in the gaseous atoms
AleksandrR [38]

Answer:

Explanation:

As you know, ionization energy is the energy needed to remove one mole of electrons from one mole of atoms in the gaseous state

X

+

energy

→

X

+

+

e

−

Right from the start, you can tell that the harder it is to remove an electron from an atom, the higher the ionization energy will be.

Now, the periodic trends for ionization energy can be describe as follows

ionization energy increases as you move from left to right across a period

ionization energy decreases as you go down a group

As you mentioned, if you compare the first ionization energies for oxygen and chlorine using these two trends, you will get conflicting results.

If you follow the way ionization energy increases across period, chlorine would have a higher ionization energy, since it's closer to the noble gases.

On the other hand, if you go by how ionziation energy decreases from top to bottom in a group, oxygen would have higher ionization energy, since it's located in period 2, as compared with period 3 for chlorine.

As it turns out, the trend for groups overpowers the trend for periods. As aresult, oxygen will have a higher ionization energy than chlorine.

This happens because the smaller oxygen atom has its outermost electrons held tighter by the nucleus. By comparison, chlorine's outermost atoms are located further away from the nucleus.

Not only that, but they are screened from the charge of the nucleus better, since they're located on the third energy level.

Oxygen's outermost electrons are screened by

2

electrons, while chlorine's are screened by

8

electrons.

All these factors will make chlorine's outermost electrons a little easier to remove, which implies a smaller ionization energy than that of oxygen.v

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3 years ago
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Answer:

Beryllium, because it is in period 2 and has four total electrons.

Explanation:

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I think its B.

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