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lys-0071 [83]
3 years ago
7

the atomic weight of antimony is 121.76 amu. two naturally occurring isotopes of antimony. 121-Sb has an isotopic mass of 120.90

38 amu and natural abundance of 57.40%. What is the isotopic mass of the other isotope, 123-Sb?
Physics
1 answer:
liubo4ka [24]3 years ago
6 0
Isotope has 57.40% abundance
the other one 100% - 57.40% = 42.60%

mass of 121 (% abundance) + mass of 123 (% abundance) =  total mass (atomic weight)
(120.9038 amu)(0.5740) + (x amu)(0.426) = 121.76 amu
x = 122.9136

hope this help
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Solution :

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Answer:

The angle of separation is  \Delta \theta =  0.93 ^o

Explanation:

From the question we are told that

    The angle of incidence is  \theta  _ i  = 56^o

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       The refractive index of red light in diamond is n_r = 2.41

      The wavelength of violet light is  \lambda _v = 400nm = 400*10^{-9}m

         The wavelength of red  light is  \lambda _r = 700nm = 700*10^{-9}m

Snell's  Law can be represented mathematically as

         \frac{sin \theta_i}{sin \theta_r} = n

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=>       sin \theta_r  =   \frac{sin \theta_i}{n}

Now considering violet light

               sin \theta_r__{v}}  =   \frac{sin \theta_i}{n_v}

substituting values

                sin \theta_r__{v}}  =   \frac{sin (56)}{2.46}

                 sin \theta_r__{v}}  =  0.337

                 \theta_r__{v}}  =  sin ^{-1} (0.337)

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substituting values

                sin \theta_r__{R}}  =   \frac{sin (56)}{2.41}

                 sin \theta_r__{R}}  =  0.344

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                 \theta_r__{R}}  = 20.12^o

The angle of separation between the red light and the violet light is mathematically evaluated as

                  \Delta \theta = \theta_r__{R}} -  \theta_r__{V}}

substituting values

                  \Delta \theta =20.12 - 19.69

                  \Delta \theta =  0.93 ^o

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