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3 years ago

Suppose a bicycle was coasting on a level surface, and there was no friction. What would happen to the bicycle?

2 answers:

5 0

If there is no friction and no horizontal force acting on the bicycle, then the bicycle keeps rolling at a constant speed in a straight line, until the cows come home, Dante's Inferno freezes over, and the POTUS accepts some responsibility for his words, actions, and consequences.

deff fn [24]3 years ago

5 0

Answer:

It would keep going at constant speed.

Explanation:

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Explain Ionic and Covalent bonding..

Elis [28]

Ionic bonding is a type of chemical bonding that involves the electrostatic attraction between oppositely charged ions, and is the primary interaction occurring in ionic compounds.A covalent bond, also called a molecular bond, is a chemical bond that involves the sharing of electron pairs between atoms. These electron pairs are known as shared pairs or bonding pairs, and the stable balance of attractive and repulsive forces between atoms, when they share electrons, is known as covalent bonding.

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3 years ago

A fisherman notices that his boat is moving up and down periodically without any horizontal motion, owing to waves on the surfac

Sedbober [7]

Answer:

v = 1.2 m/s

Explanation:

The wavelength of the waves is given as the horizontal distance between the crests:

λ = wavelength = 5.5 m

Now, the time period is given as the time taken by boat to move from the highest point again to the highest point. So it will be equal to twice the time taken by the boat to travel from highest to the lowest point:

T = Time Period = 2(2.3 s) = 4.6 s

Now, the speed of the wave is given as:

$v = f\lambda$

where,

v= speed of wave = ?

f = frequency of wave = $\frac{1}{T} = \frac{1}{4.6\ s} = 0.217\ Hz$

Therefore,

$v = (0.217\ Hz)(5.5\ m)\\$

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3 years ago

A tuning fork with a frequency of 404 Hertz is struck with a soft hammer. The fork is struck a second time by the

Bas_tet [7]

Answer:

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Explanation:

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3 years ago

A very long train is rolling at 4 m/s along a straight track. An observer is standing on the ground very dangerously close to th

hichkok12 [17]

Answer:

A. $\vec{r}=(6\frac{m}{s})t\ \ \hat{i}$

B. t = 50 s

Explanation:

A. The vectorial equation of the person who is getting closer to the other person is:

$\vec{r}=\vec{v}t$

r: position vector

v: speed vector = 6m/s i (if you consider the motion as a horizontal motion)

Then, you replace and obtain:

$\vec{r}=(6\frac{m}{s})t\ \ \hat{i}$

B. The time is:

$t=\frac{d}{v}$

d: distance to the observer = 300m

v: speed of the person on the car = 6.00 m/s

$t=\frac{300m}{6m/s}=50s$

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3 years ago

Define orbital velocity

sveta [45]

the Orbital Velocity is the velocity sufficient to cause a natural or artificial satellite to remain in orbit. Inertia of the moving body tends to make it move on in a straight line, while gravitational force tends to pull it down. The orbital path, elliptical or circular, representing a balance between gravity and inertia, and it follows a rue that states that the more massive the body at the centre of attraction is, the higher is the orbital velocity for a particular altitude or distance.

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3 years ago