Question

An electron starts from rest in a vacuum, in a region of strong electric field. The electron moves through a potential difference of 36 volts. What is the kinetic energy of the electron in electron volts (eV)

Answer 1

Answer:

The kinetic energy is  $KE = 5.67*10^{-18} \ J$

Explanation:

From the question we are told that

    The potential difference is  $\Delta V = 36 \ volts$

       

The potential energy of the end  is mathematically represented as

        $PEs = - q * \Delta V$

q  is the charge on an electron with a constant value of $q = 1.60 *10^{-19} \ C$

       substituting values

      $PE = - 1.60*10^{-19} * 36$

      $PE = - 5.67*10^{- 18} \ J$

Now from the law of energy conservation

     The $PE_e = KEe$

Where  $KE _e$ is the potential  energy at the end

 So  

        $KE = 5.67*10^{-18} \ J$

The  negative sign is not includes because kinetic energy can not be negative