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svet-max [94.6K]
3 years ago
7

View the photo below, read the passage, and answer the question.

Physics
1 answer:
Furkat [3]3 years ago
7 0
The answer is a i hope this helps you have a great time
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Which law of thermodynamics would be violated if heat were to spontaneously flow between two objects of equal temperature?
maks197457 [2]
<span>Actually the second law of thermodynamics would truly gets violated ie, which means that the entrophy changes of the isolated system can never be negative, which covers the above that if heat were to spontaneously flow between any two objects of equal temperature would be fully violated.</span>
5 0
3 years ago
The chart shows the percentage of different elements in the human body.
GenaCL600 [577]
I believe that answer is nitrogen.
8 0
3 years ago
A 10.0kg water balloon is dropped from a height of 12.0m. Calculate the speed of the balloon just before it hits the ground
kolbaska11 [484]

Answer:

15.5 m/s.

Explanation:

Potential energy of the balloon has been converted to kinetic energy.

potential energy = kinetic energy.

mgh = ½mv².

10* 10* 12= ½ *10 *v²

1200 = 5v²

v²=1200÷5

v=√240

v= 15.49~15.5 m/s.

5 0
3 years ago
Calculate the maximum absolute uncertainty for R if:
Radda [10]

Answer:

ΔR = 9 s

Explanation:

To calculate the propagation of the uncertainty or absolute error, the variation with each parameter must be calculated and the but of the cases must be found, which is done by taking the absolute value

           

The given expression is      R = 2A / B

the uncertainty is                 ΔR = | \frac{dR}{dA} | ΔA + | \frac{ dR}{dB} | ΔB

we look for the derivatives

     \frac{dR}{dA} = 9 / B

     \frac{dR}{dB} = 9A ( - \frac{1}{B^2 } )

we substitute

     ΔR = \frac{9}{B}  ΔA + \frac{9A}{B^2}  ΔB

the values ​​are

     ΔA = 2 s

     ΔB = 3 s

 

     ΔR = \frac{9}{11}   2 + \frac{9 \ 32}{11^2 }  3

     ΔR = 1.636 + 7.14

     ΔR = 8,776 s

the absolute error must be given with a significant figure

     ΔR = 9 s

3 0
3 years ago
I need help with this question, please
Burka [1]
Ok so this is a kinetic and potential energy problem. KE= 1/2*m*v^2 and PE= mgh so we set them equal to each other and get KE=PE so 1/2mv^2=mgh so mass divers out and left with 1/2v^2 =gh so solving for h or height we get
h=(1/2v^2)/g so h= 1/2*(6.5m/s)^2/9.80m/s^2 = 2.16m in height the ball will reach.

Hope this helps! Any questions please just ask!
Please rate to help me out also! Thank you so much!!!
3 0
4 years ago
Read 2 more answers
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