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just olya [345]
2 years ago
8

What net is required to push a sofa with a mass of 59 kilograms so that it accelerates at 9.75 meters/second^2 (assume a flat,fr

ictionless surface.)

Physics
1 answer:
stich3 [128]2 years ago
8 0

Newton's 2nd Law of Motion:  Force = (mass) · (acceleration)

Do I need to go any further ?

I get  575.25 Newtons .

Oh !  Look at that !  Right there at the top, it says "Using Newton's Second Law".  This might have suggested to you that maybe you could solve the problem by using Newton's Second Law.

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A spring with spring constant of 34 N/m is stretched 0.12 m from its equilibrium position. How much work must be done to stretch
Nesterboy [21]

Answer:0.253Joules

Explanation:

First, we will calculate the force required to stretch the string. According to Hooke's law, the force applied to an elastic material or string is directly proportional to its extension.

F = ke where;

F is the force

k is spring constant = 34N/m

e is the extension = 0.12m

F = 34× 0.12 = 4.08N

To get work done,

Work is said to be done if the force applied to an object cause the body to move a distance from its initial position.

Work done = Force × Distance

Since F = 4.08m, distance = 0.062m

Work done = 4.08 × 0.062

Work done = 0.253Joules

Therefore, work done to stretch the string to an additional 0.062 m distance is 0.253Joules

8 0
3 years ago
A person drives north 3 blocks, then turns east and drives 3 blocks. The driver then turns south and drives 3 blocks. How could
KonstantinChe [14]

Answer:by driving east 3 blocks from the starting point

Explanation:)

4 0
3 years ago
what is the acceleration of each body of mass 5kg rests on a frictionless table and is connected to a cable that passes over a p
Oksanka [162]

Answer:

6.53 m/s²

Explanation:

Let m₁ = 5 kg and m₂ = 10 kg. The figure is attached and free body diagrams of the objects are also attached.

Both objects (m₁ and m₂) have the same magnitude of acceleration(a). Let g be the acceleration due to gravity = 9.8 m/s². Hence:

T = m₁a               (1)

m₂g - T = m₂a    (2)

substituting T = m₁a in equation 2:

m₂g - m₁a = m₂a

m₂a + m₁a = m₂g

a(m₁ + m₂) = m₂g

a = m₂g / (m₁ + m₂)

a = (10 kg * 9.8 m/s²) / (10 kg + 5 kg) = 6.53 m/s²

Both objects have an acceleration of 6.53 m/s²

8 0
3 years ago
By the 2nd century BCE the ____ democratized astrology<br> A. Greeks<br> B. Egyptians<br> C. Romans
elena-14-01-66 [18.8K]

Answer:

A

Explanation:

3 0
3 years ago
Coulomb's Law: Two identical small charged spheres are a certain distance apart, and each one initially experiences an electrost
Ahat [919]

Answer:

The magnitude of electrostatic force on each charge is quarter of the magnitude of initial electrostatic force. ( ¹/₄ F)

Explanation:

The electrostatic force between two charges is given by Coulomb's law;

F = \frac{kQ_1Q_2}{r^2}

where;

Q₁ and Q₂ are the magnitude of the charges

r is the distance between the charges

k is Coulomb's constant

Since the charges are identical;

Q₁ = Q

Q₂ = Q

the electrostatic force experienced by each charge is given by;

F =  \frac{kQ^2}{r^2}

When each of the spheres has lost half of its initial charge;

Q₁ = Q/2

Q₂ = Q/2

F_2 = \frac{k(Q/2)(Q/2)}{r^2}\\\\ F_2 = \frac{k(Q)(Q)}{4r^2}\\\\F_2 = \frac{1}{4} (\frac{kQ^2}{r^2} )\\\\F_2 = \frac{1}{4} (F)

Therefore, the magnitude of electrostatic force on each charge is quarter of the magnitude of initial electrostatic force.

6 0
2 years ago
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