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3 years ago

Which

Physics

2 answers:

Vesna [10]3 years ago

7 0

Answer:

Should be Venus

Explanation:

satela [25.4K]3 years ago

4 0

Answer: The answer is Venus!

Explanation: Venus has the longest day of any planet in our solar system. It completes one rotation every 243 Earth days. Its day lasts longer than its orbit.

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Weddell seals make holes in sea ice so that they can swim down to forage on the ocean floor below. Measurements for one seal sho

Mariulka [41]

Answer:

B. 1 m/s

Explanation:

Metric unit conversions:

0.3 km = 300m

5 minutes = 5*60 = 300 seconds

So if a seal can reach a depth of 300m in a time of 300 seconds, its diving speed is the distance divided by time duration

v = s/t = 300/300 = 1m/s

So B is the correct answer

3 0

3 years ago

An electron is projected with an initial speed vi = 4.60 × 105 m/s directly toward a very distant proton that is at rest. Becaus

frutty [35]

Answer:

$2.99\times 10^{-19}\ m$

Explanation:

Given:

$u$ = initial velocity of the electron = $4.60\times 10^5\ m/s$

$v$ = final velocity of the electron = $3u$

$x$ = initial position of the electron from the proton = very distant = $\infty$

Assume:

$m$ = mass of an electron = $9.1\times10^{-31}\ kg$

$e$ = magnitude of charge on an electron = $1.6\times10^{-19}\ C$

$p$ = magnitude of charge on an proton = $1.6\times10^{-19}\ C$

$k$ = Boltzmann constant = $9\times 10^9\ Nm^2/C^2$

$y$ = final position of the electron from the proton

$\Delta K$ = change in kinetic energy of the electron

$W$ = work done by the electrostatic force

$F$ = electrostatic force

$r$ = instantaneous distance of the electron from the proton

Let us first calculate the work done by the electrostatic force.

$W=\int Fdr\\\Rightarrow W = \int \dfrac{kep}{r^2}dr\\\Rightarrow W = kep\int \dfrac{1}{r^2}dr\\\Rightarrow W = kep\left | \dfrac{1}{r} \right |_{y}^{x}\\\Rightarrow W = kep\left ( \dfrac{1}{x}-\dfrac{1}{y} \right )\\\Rightarrow W = kep\left ( \dfrac{1}{x}-\dfrac{1}{\infty} \right )\\\Rightarrow W =\dfrac{kep}{x}$

Using the principle of the work-energy theorem,

As only the electrostatic force is assumed to act between the two charges, the kinetic energy change of the electron will be equal to the work done by the electrostatic force on the electron due to proton.

$\therefore \Delta K = W\\\Rightarrow \dfrac{1}{2}m(v^2-u^2)= \dfrac{kep}{x}\\\Rightarrow \dfrac{1}{2}m((3u)^2-u^2)= \dfrac{kep}{x}\\\Rightarrow \dfrac{1}{2}m(8u^2)= \dfrac{kep}{x}\\\Rightarrow x= \dfrac{2kep}{8mu^2}\\\Rightarrow x= \dfrac{2\times 9\times 10^9\times 1.6\times10^{-19}\times 1.6\times10^{-19}}{8\times 9.1\times10^{-31}\times (4.60\times 10^5)^2}\\\Rightarrow x=2.99\times 10^{-10}\ m\leq$

Hence, the electron is at a distance of $2.99\times 10^{-10}\ m$ when the electron instantaneously has speed of three times the initial speed.

8 0

4 years ago

Car B is being pushed by a force of 22000 N. If it has a mass of 1375 kg.,

Burka [1]

Answer:

a = 16 m/s²

General Formulas and Concepts:

Dynamics

Newton's Law of Motions

Newton's 1st Law of Motion: An object at rest remains at rest and an object in motion stays in motion
Newton's 2nd Law of Motion: F = ma (Force is equal to [constant] mass times acceleration)
Newton's 3rd Law of Motion: For every action, there is an equal and opposite reaction

Explanation:

Step 1: Define

Identify variables

[Given] F = 22000 N

[Given] m = 1375 kg

[Solve] a

Step 2: Find Acceleration

Substitute in variables [Newton's 2nd Law of Motion]: 22000 N = (1375 kg)a
Isolate a: 16 m/s² = a
Rewrite: a = 16 m/s²

5 0

3 years ago

A man jogs at a velocity of 2.5 m/s west for 1,200 s. He then walks at a velocity 1.0 m/s east for 500 s and then stops to rest

olganol [36]

Speed of man towards West =2.5 m/s

Time to travel in the given direction = 1200 s

Total displacement towards west

$d_1 = v_1 t$

$d_1 = 2.5 \times 1200 = 3000 m$

Now speed of man towards East = 1 m/s

time to travel in east direction = 500 s

total displacement towards East

$d_2 = v_2 t$

$d_2 = 1 \times 500 = 500 m$

Now total displacement will be

$d = d_1 - d_2$

$d = 3000 - 500 = 2500 m$

so it is 2500 m towards west

5 0

3 years ago

13) Fred is travelling 3.4 m/s and decelerates at a rate of 0.83 m/s until he comes to a stop

Finger [1]

Answer:

<h2>Tt will take 4.04 seconds</h2>

Explanation:

In this problem/exercise, we are going to apply the newtons first equation of motion to solve for the time taken

Given that

final velocity= 3.4m/s

initia velocity u= 0m/s

deceleration= 0.84 m/s^2

time t= ?

applying

v=u+at

Substituting our given data into the expression above we have

3.4=0+0.84t

3.4=0.84t

divide both sides by 0.84 we have

3.4/0.84= t

t= 4.04 seconds

3 0

3 years ago