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satela [25.4K]
3 years ago
14

What other ways could a wildfire be contained, extinguished, or slowed down?

Engineering
1 answer:
galben [10]3 years ago
3 0
Back burning, starting fires infront of the main fire to prevent the fire from spreading and depleting fuel for the fire, digging trenches so the fire has no where to go, dropping water from planes or helicopters.
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Calculate the modulus of elasticity of carbon-epoxy composite under isostraincondition if thecomposite consists of 40% carbon fi
Artyom0805 [142]

Answer:

1. 142.1 GPa

2. 98.52%

Explanation:

1. The modulus of elasticity of carbon-epoxy composite is calculated using the following formula:

Ec = VmEm + VfEf

where Vm: volume of Epoxy

            Em: modulus of the elasticity of the epoxy

            Vf: volume of carbon fiber

             Ef: modulus of the elasticity of the carbon fiber

Given that :

          Vm = 0.6

            Em = 3.5 GPa

            Vf = 0.4

             Ef: 350 Gpa

Therefore Ec = (0.6 × 3.5 GPa + (0.4 × 350 GPa)

Ec = 142.1 GPa

The modulus of elasticity of carbon-epoxy composite is 142.1 GPa

2. Percentage of load carried by the carbon fibers is given by the following equation: Ff/Fc = (Ef/Ec)×Vf

where Ff is the force carried by carbon fibers, Fc is the force applied to the composite, Ec is the modulus of elasticity of the composite,  Ef is the  modulus of the elasticity of the carbon fiber and Vf  the volume of carbon fiber.

Given that:

       EF = 350 Gpa

        Ec = 142.1 GPa

         Vf = 0.4

Substituting the above values into the equation:

Ff/Fc = (350 GPa/142.1 GPa)×0.4 = 0.9852 = 98.52%

The percentage of load carried by the carbon fibers is there 98.52%

8 0
3 years ago
(a) Design a low-pass filter with a cutoff frequency of 12 kHz. Use0.15 uF capacitor and an appropriate resistor. B) Sketch and
pychu [463]

Answer:

A) 88.42 ohms

c) 0.5145 and - 5.77 db

Explanation:

A)  Value of cut-off frequency = 12 kHz

capacitance of capacitor =0.15 microF

formula for cut-off frequency of a low-pass filter

Fc = \frac{1}{2\pi RC}   making R the subject of the formula in other to get the resistance of the low pass filter resistor

R = \frac{1}{2\pi (12*10^3)(0.15*10^{-6} )} = 88.42 OHMS

attached is the solution for B and C

3 0
4 years ago
How is the minimum circuit ampacity for an air-conditioning condensing unit calculated?
horsena [70]
The answer is 1. Hopefully it helps!
5 0
3 years ago
The inlet for a high-bypass-ratio turbofan engine has an area A1 of 6.0 m 2 and is designed to have an inlet Mach number M~ of 0
Lelu [443]

Answer:

The additive drag at flight condition will be found by the following equation

Area = A1 = 6m2

Da = Additive drag

Cda = Additive drag coefficient

P = prassure at altitude of 12Km

Po = Prassure at sea level

 \gamma = Ratio of specific heat capacity

The formula of additive drag is given below

D = Cda q A

q = Dynamic prassure , A = cross sectional area

q =( \gamma/ 2) P0 M02

    D = Cda ( \gamma/2) po Mo2 A

Cda=0.32

 \gamma=1.4

M=0.8

p0= 101325pa

D = 0.32 (1.4/2)(101325pa)(0.6)2 6

D = 49025N

Explanation:

The additive drag at the flight conditions will be D= 49025N

8 0
3 years ago
An aircraft component is fabricated from an aluminum alloy that has a plane strain fracture toughness of 40 . For an applied str
erma4kov [3.2K]

Answer:

B. 2.3mm

Explanation:

The correct answer for the given question is B. 2.3mm. Some aircraft are made are fabricated from aluminium which has plane stain fracture toughness. In the given scenario the plane stain toughness is

Ktc = 40 [ MPa \sqrt{(m)} ]

When the Ktc increases the fracture will appear on the aircraft. In this case the maximum crack until the fracture failure is 2.5mm.

8 0
3 years ago
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