Question

In introductory physics laboratories, a typical Cavendish balance for measuring the gravitational constant G uses lead spheres with masses of 1.60 kg and 16.0 g whose centers are separated by about 3.30 cm. Calculate the gravitational force between these spheres, treating each as a particle located at the center of the sphere.

Answer 1

Answer:

The value is  $F = 1.568 *10^{-9} \ N$

Explanation:

From the question we are told that

     The mass  of the first lead sphere is $m = 1.60 \ kg$

      The mass of the second lead sphere is  $M = 16 \ g = 0.016 \ kg$

      The separation between masses is  $r = 3.30 \ cm = 0.033 \ m$

     

Generally the gravitational force between each sphere is mathematically represented as

          $F = \frac{G * m * M }{r^2 }$

Here G is the gravitational constant with value  $G = 6.67 *10^{-11 } \ m^3 \cdot kg^{-1} \cdot s^{-2}$

         $F = \frac{6.67 *10^{-11 } * 1.60 * 0.016 }{0.033^2 }$

=>       $F = 1.568 *10^{-9} \ N$