Answer:
Valvular stenosis , Valvular prolapse , Regurgitation,
Explanation:
Answer:
676 ft
Explanation:
Minimum sight distance, d_min
d_min = 1.47 * v_max * t_total where v_max is maximum velocity in mi/h, t_total is total time
v_max is given as 50 mi/h
t_total is sum of time for right-turn and adjustment time=8.5+0.7=9.2 seconds
Substituting these figures we obtain d_min=1.47*50*9.2=676.2 ft
For practical purposes, this distance is taken as 676 ft
Answer:
a)Percent reduction in area=54.23 %
b)Percent elongation=32.87 %
Explanation:
Given that
Di= 11.53 mm
Df= 7.80 mm
Li= 51.4 mm
Lf= 68.3 mm
A= π/4 D²
a)
Percent reduction in area ,RA
![RA=\dfrac{A_i-A_f}{A_i}\times 100](https://tex.z-dn.net/?f=RA%3D%5Cdfrac%7BA_i-A_f%7D%7BA_i%7D%5Ctimes%20100)
![RA=\dfrac{D_i^2-D_f^2}{D_i^2}\times 100](https://tex.z-dn.net/?f=RA%3D%5Cdfrac%7BD_i%5E2-D_f%5E2%7D%7BD_i%5E2%7D%5Ctimes%20100)
![RA=\dfrac{11.53^2-7.8^2}{11.53^2}\times 100](https://tex.z-dn.net/?f=RA%3D%5Cdfrac%7B11.53%5E2-7.8%5E2%7D%7B11.53%5E2%7D%5Ctimes%20100)
RA= 54.23 %
Percent reduction in area=54.23 %
b)
Percent elongation EL
![EL=\dfrac{L_f-L_i}{L_i}\times 100](https://tex.z-dn.net/?f=EL%3D%5Cdfrac%7BL_f-L_i%7D%7BL_i%7D%5Ctimes%20100)
![EL=\dfrac{68.3-51.4}{51.4}\times 100](https://tex.z-dn.net/?f=EL%3D%5Cdfrac%7B68.3-51.4%7D%7B51.4%7D%5Ctimes%20100)
EL=32.87 %
Percent elongation=32.87 %
Answer:
B
Explanation:
A robot's work envelope is its range of movement. It is the shape created when a manipulator reaches forward, backward, up and down. These distances are determined by the length of a robot's arm and the design of its axes. ... A robot can only perform within the confines of this work envelope.