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3 years ago

How does the modern Diesel engine achieve higher power output without the use of higher compression ratio?

Engineering

1 answer:

krok68 [10]3 years ago

3 0

Explanation:

We know that the efficiency of diesel engine given as follows

$\eta=1-\dfrac{\rho^{\gamma}-1}{r^{\gamma-1}\gamma(\rho-1)}$

Where r is the compression ratio ,ρ is the cut off ratio and γ is the heat capacity ratio .

Here given that we want to increase the efficiency with out changing the compression ratio.

So from the efficiency formula we can say that when cut off ratio is decreases then the efficiency of diesel cycle will increases.When efficiency is high it means that the power output of engine is high.

The second method to increase the efficiency of diesel engine is that ,use the anti knocking diesel.Use premium diesel instead of use the normal diesel fuel.

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For the system in problem 4, suppose a main memory access requires 30ns, the page fault rate is .01%, it costs 12ms to access a

raketka [301]

Answer:

a. 7.75

b. 24.4

Explanation:

The Operating system uses virtual memory and page tables maps these virtual address to physical address. TLB works as a cache for such mapping.

program >>> TLB >>> cache >>> Ram

A program search for a page in TLB, if it doesn't find that page it's a TLB miss and then further looks for the page in cache.

If the page is not in cache then it's a cache miss and further looks for the page in RAM.

If the page is not in RAM, then it's a page fault and program look for the data in secondary storage.

So, typical flow would be

Page Requested >> TLB miss >> cache miss >>main memory>> page fault >> looks in secondary memory.

Here,

Main memory access time= 30 ns

Page fault rate=.01%

page fault service time= 12ns

TLB access time=7 ns

TLB hit rate= .95%

TLB miss rate =1-.95=.05%

cache access time = 15 ns

cache miss rate= .3%

cache hit rate = 1-.3=.97%

So,

a) TLB hit time= TLB access time = 7 ns

cache hit time = TLB hit rate * TLB access time + TLB miss rate * ( TLB access time + cache hit time)

= .95 * 7 + .05 * (7+15)

= 7.75 ns

b) EAT for TLB hit= 7ns

Total EAT = TLB hit rate *( TLB access time + Cache hit rate * cache access time + cache miss rate * (cache + main memory access time))+ TLB miss rate ( TLB access time + main memory access time + cache hit rate * cache access time + cache miss rate ( cache + main memory access time))

= .95 *( 7 + (.97*15) + .03(15+30))+ .05*(7+30+(.97*15) + .03 ( 15 + 30))=24.4 ns

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3 years ago

The annual storage in Broad River watershed is 0 cm/y. Annual precipitation is 100 cm/y and evapotranspiration is 50 cm/y. The s

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Answer:

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Explanation:

See attachment

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Lynna [10]

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3 years ago

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Len [333]

Answer:

forwarder

Explanation:

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3 years ago

Suppose the working pressure for a boiler is 10 psig, then what is the corresponding absolute pressure?

yanalaym [24]

Answer:

The corresponding absolute pressure of the boiler is 24.696 pounds per square inch.

Explanation:

From Fluid Mechanics, we remember that absolute pressure ( $p_{abs}$ ), measured in pounds per square inch, is the sum of the atmospheric pressure and the working pressure (gauge pressure). That is: