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jeka94
2 years ago
10

A) Your friend is faced with a situation i n whi ch t here is a difficulty in

Engineering
1 answer:
Arlecino [84]2 years ago
7 0

The Steps my friend need to make an ethical decision are:

  • Step One: He or she needs to define the Problem.
  • Step Two: He or she needs to find out possible Resources to solve the problem and then  Brainstorm on the  List for the Potential Solutions to the problem.
  • Step Three : Evaluate and examine those Alternatives. ...
  • Step Four : Make his or her Decision, Implement It and then examine your Decision.

<h3>What is ethical decision model?</h3>

An ethical decision-making model is known to be a kind of a tool that can be used by a person to help create the ability to think in regards to an ethical dilemma and come to an ethical decision.

Note that Ethical decision-making is one that is dependent on the key character values such as trustworthiness, respect, role, fairness,  and others.

Therefore, The Steps my friend need to make an ethical decision are:

  • Step One: He or she needs to define the Problem.
  • Step Two: He or she needs to find out possible Resources to solve the problem and then  Brainstorm on the  List for the Potential Solutions to the problem.
  • Step Three : Evaluate and examine those Alternatives. ...
  • Step Four : Make his or her Decision, Implement It and then examine your Decision.

Learn more about ethical decision from

brainly.com/question/21105288

#SPJ1

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Differentiate between "Threshold and Resolution" with suitable examples.
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On some late model cars, climate control systems wil create trouble codes for trouble shooting purposes.
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In a wheatstone bridge three out of four resistors have of 1K ohm each ,and the fourth resistor equals 1010 ohm. If the battery
Dima020 [189]

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  248.756 mV

  49.7265 µA

Explanation:

The Thevenin equivalent source at one terminal of the bridge is ...

  voltage: (100 V)(1000/(1000 +1000) = 50 V

  impedance: 1000 || 1000 = (1000)(1000)/(1000 +1000) = 500 Ω

The Thevenin equivalent source at the other terminal of the bridge is ...

  voltage = (100 V)(1010/(1000 +1010) = 100(101/201) ≈ 50 50/201 V

  impedance: 1000 || 1010 = (1000)(1010)/(1000 +1010) = 502 98/201 Ω

__

The open-circuit voltage is the difference between these terminal voltages:

  (50 50/201) -(50) = 50/201 V ≈ 0.248756 V . . . . open-circuit voltage

__

The current that would flow is given by the open-circuit voltage divided by the sum of the source resistance and the load resistance:

  (50/201 V)/(500 +502 98/201 +4000) = 1/20110 A ≈ 49.7265 µA

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