Answer:
The centripetal force on body 2 is 8 times of the centripetal force in body 1.
Explanation:
Body 1 has a mass m, and its moving in a circle with a radius r at a speed v. The centripetal force acting on it is given by :
Body 2 has a mass 2m and its moving in a circle of radius 4r at a speed 4v. The centripetal force on body 2 is :
So, the centripetal force on body 2 is 8 times of the centripetal force in body 1.
Answer:
w = 0.189 rad/ s
Explanation:
This exercise we work with the conservation of the moment, the system is made up of the merry-go-round and the child, for which we write the moment of two instants
Initial
L₀ = I₀ w₀
Final
= I w
L₀ = L_{f}
I₀ w₀ = I_{f} w
.w = I₀/I_{f} w₀
The initial moment of inertia is
I₀ = 500 kg. m2
The final moment of inertia
= 500 + m r²
I_{f} = 500 + 20 1.5
I_{f} = 530 kg m²
Initial angular velocity
w₀ = 0.20 rad / s
Let's calculate
w = 500/530 0.20
w = 0.189 rad / s
Answer:
Their speed immediately after the collision is 60 km/h
Explanation:
The magnitude that characterizes the state of motion of a body is called the quantity of motion. The momentum of a particle of mass m moving with velocity v is defined as the product of mass and velocity:
p=m*v
Newton's second law states that to accelerate an object you must apply a force to it. In other words, to change the moment of an object, an impulse must be applied to it, an impulse that is produced by a force. In both cases there is an external agent that exerts the force or the impulse, the internal forces are not considered. When the force net is zero, so the net momentum is zero, and therefore there is no change in total momentum. Then it can be stated that if a net force is not exerted on a system, the total moment of the system cannot change.
In summary, the principle of conservation of linear momentum, also known as the principle of conservation of momentum, states that if the resultant of the forces acting on a body or system is zero, its momentum remains constant in time.
Then before collision, the momentum of truck is 1,500 kg*80 km/h = 120,000 kg.km/h and the momentum of car is 1,000 kg* 30 km/h = 30,000 kg.km/h
So, the total momentum before collision is 120,000 kg*km/h+ 30,000 kg*km/h = 150,000 kg.km/h
The two cars stick together after the collision. This means that the speed V of both is the same. Therefore, the momentum after collision is
V*(1,500 kg + 1,000 kg) = V*2,500 kg
Applying the law of conservation of momentum, that it states that the total momentum of two objects before collision is equal to the total momentum of the two objects after collision., you get:
150,000 kg.km/h= V*2,500 kg
Solving:
V= 60 km/h
<u><em>Their speed immediately after the collision is 60 km/h</em></u>