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daser333 [38]
2 years ago
9

The speed of sound is 346 m/s. If a sound wave travels at a frequency of 55 Hz, what would its wavelength be?​

Physics
1 answer:
Korvikt [17]2 years ago
3 0

Answer:

6.29 meters.

Explanation:

, where v is the speed of wave and f is the frequency of wave.

We are given that ,

The speed of sound is 346 m/s.

i..e v=346 m/s

A sound wave travels at a frequency of 55 H.

i..e f=55

the wavelength would be 6.29 meters.

This is based on another brainly answer

Link: brainly.com/question/12538018

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it's called inbreeding


7 0
3 years ago
A 4.5 g coin sliding to the right at 23.8 cm/s makes an elastic head-on collision with a 13.5 g coin that is initially at rest.
Airida [17]

Answer:

a) v = 11.9\times 10^{-2}\,\frac{m}{s} \,(11.9\,\frac{cm}{s} ), b) \Delta K = 9.559\times 10^{-5}\,J

Explanation:

a) The final velocity of the 13.5 g coin is found by the Principle of Momentum Conservation:

(4.5\times 10^{-3}\,kg)\cdot (23.8\times 10^{-2}\,\frac{m}{s} )+(13.5\times 10^{-3}\,kg})\cdot (0\,\frac{m}{s} ) = (4.5\times 10^{-3}\,kg)\cdot (-11.9\times 10^{-2}\,\frac{m}{s} )+(13.5\times 10^{-3}\,kg})\cdot v

The final velocity is:

v = 11.9\times 10^{-2}\,\frac{m}{s} \,(11.9\,\frac{cm}{s} )

b) The change in the kinetic energy of the 13.5 g coin is:

\Delta K = \frac{1}{2}\cdot (13.5\times 10^{-3}\,kg)\cdot \left[(11.9\times 10^{-2}\,\frac{m}{s} )^{2}-(0\,\frac{m}{s} )^{2}\right]

\Delta K = 9.559\times 10^{-5}\,J

4 0
3 years ago
Read 2 more answers
Which amusement park ride utilizes periodic motion?
hjlf
Periodic motion implies that the ride oscillates back and forth. The period is the time it takes to complete one cycle. Therefore it would be the swing.
6 0
3 years ago
Which statement is true about Car A?
alexira [117]

Answer:

Car A has a velocity of 40 km/hr  west.

Explanation:

The velocity of an object is a vector quantity. It has both magnitudes as well as direction.

Arrows are used to show direction.

Car A is moving towards west. Car B is moving towards east-south direction. Car C is moving towards South direction. Car E is moving towards North direction.

So, the correct option is (a) i.e. Car A has a velocity of 40 km/hr  west.

6 0
2 years ago
How much work does the electric field do in moving a proton from a point with a potential of +155 v to a point where it is -65 v
Zigmanuir [339]
The work done by the electric field is equal to the loss of electric potential energy of the proton in moving from its initial location to its final location:
W=-\Delta U = -q \Delta V = -q (V_f -V_i)
where q=1.6 \cdot 10^{-19}C is the proton charge, V_f = -65 V and V_i=+155 V are the voltages in the final and initial locations. Substituting, we get
W=-(1.6 \cdot 10^{-19}C)(-65 V-(+155 V))=3.5 \cdot 10^{-17}J
7 0
3 years ago
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