Ask question

Ask question

All categories

3 years ago

12

The graph shows a ball rolling from A to G. At which point does the ball have the greatest kinetic energy?

2 answers:

Oduvanchick [21]3 years ago

7 0

Answer:

The will have its greatest kinetic energy just after the ball has started moving since kinetic energy is the energy that possess moving objects.

AysviL [449]3 years ago

3 0

please give garph picture

You might be interested in

Please help this is for my final exam

ki77a [65]

Answer:

A

Explanation:

5 0

3 years ago

Calcite (CaCO_3) is a crystal with abnormally large birefringence. The index of refraction for light with electric field paralle

katrin2010 [14]

Answer:

(a) 42.28°

(b) 37.08°

Explanation:

From the principle of refraction of light, when light wave travels from one medium to another medium, we have:

$\frac{n_{b} }{n_{a} }$ = sinθ $_{a}$ /sinθ $_{b}$

In the given problem, we are given the refractive indices of light which are parallel and perpendicular to the axis of the optical lens as 1.4864 and 1.6584 respectively.

For critical angle θ $_{a}$ = θ $_{c}$ , θ $_{b}$ = 90°; $n_{b} = 1$

(a) $n_{a} = 1.4864$

$\frac{1 }{1.4864 }$ = sinθ $_{c}$ /sin90°

0.6728 = sinθ $_{c}θ[tex]_{c} = sin^(-1) 0.6728 = 42.28°(b) [tex]n_{a} = 1.6584$

$\frac{1 }{1.6584}$ = sinθ $_{c}$ /sin90°

0.60299 = sinθ[tex]_{c}

θ[tex]_{c} = sin^(-1) 0.60299 = 37.08°

7 0

3 years ago

A 21.3 A current flows in a long, straight wire. Find the strength of the resulting magnetic field at a distance of 45.7 cm from

Bezzdna [24]

Answer:

The magnetic field strength due to current flowing in the wire is9.322 x 10⁻⁶ T.

Explanation:

Given;

electric current, I = 21.3 A

distance of the magnetic field from the wire, R = 45.7 cm = 0.457 m

The strength of the resulting magnetic field at the given distance is calculated as;

$B = \frac{\mu_o I}{2\pi R}$

Where;

μ₀ is permeability of free space = 4π x 10⁻⁷ T.m/A

$B = \frac{\mu_o I}{2\pi R}\\\\B = \frac{4\pi*10^{-7} *21.3}{2\pi(0.457)}\\\\B = 9.322 *10^{-6} \ T$

Therefore, the magnetic field strength due to current flowing in the wire is 9.322 x 10⁻⁶ T.

7 0

3 years ago

Find distance traveled when a donkey took 20 sec to fall from a cliff at 9.8 m/s2

musickatia [10]

Distance= speed * time
So multiply speed and time to get the value of distance
20*9.8 =196 meters

8 0

3 years ago

Jack and Jill are maneuvering a 3300 kg boat near a dock. Initially the boat's position is < 2, 0, 3 > m and its speed is

Paraphin [41]

Answer:

The workdone by Jack is $W_{jack} = -1050J$

The workdone by Jill is $W_{Jill} = 0J$

The final velocity is $v = 1.36 m/s$

Explanation:

From the question we are given that

The mass of the boat is $m_b = 3300kg$

The initial position of the boat is $P_i = (2 \r i + 0 \r j + 3\r k)m$

The Final position of the boat is $P_f = (4\r i + 0 \r j + 2\r k )\ m$

The Force exerted by Jack $\r F = (-420\r i + 0 \r j + 210\r k) \ N$

The Force exerted by Jill $\r F_{Jill} =(180 \r i + 0\r j + 360\r k)$

Now to obtain the displacement made we are to subtract the final position from the initial position

$\r P = P_f - P_i$

$= (4\r i + 0\r j + 2 \r k) - (2\r i + 0\r j + 3\r k )$

$= (2\r i + 0\r j -\r k )m$

Now that we have obtained the displacement we can obtain the Workdone

which is mathematically represented as

$W =\r F * \r P$

The amount of workdone by jack would be

$W_{jack} =\r F * \r P$

$= [(-420\r i +0\r j +210\r k)(2\r i + 0\r j - \r k)]$

$= (-420) (2) + (210)(-1)$

$= -840 - 210$

$=-1050J$

The amount of workdone by Jill would be

$W_{Jill} =\r F * \r P$

$= [(180 \r i + 0\r j + 360\r k)(2\r i +0\r j -\r k)]$

$= (180 )(2) +(360)(-1)$

$=0J$

According to work energy theorem the Workdone is equal to the kinetic energy of the boat

$W = K.E = \frac{1}{2} m *[v^2 - (1.1)^2]$

$-1050 = 0.5*3300 [*v^2- (1.1)^2]$

$-1050 = 1650 [v^2 -1.21]$

$0.6363 = v^2 -1.21$

$v^2 = 0.6363+1.21$

$v^2 =1.846$

$v = 1.36\ m/s$

6 0

3 years ago