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zimovet [89]
3 years ago
5

A complete path through which charge can flow is an electric what?

Physics
2 answers:
grigory [225]3 years ago
5 0
<span>A complete path through which charge can flow is an "Electric Circuit"

Hope this helps!</span>
kvasek [131]3 years ago
3 0

Answer: The correct answer is "electric circuit"

Explanation:

Electric circuit: It is a path through which the charges can flow easily. It is a path for transmitting electric current.

It is a continuous path through which the electrons can flow in the closed circuit. The flow of charges constitutes the current in the circuit. The battery makes the charges flow in the circuit or voltage source.

If the current is flowing in the electric circuit then it is said to be closed electric circuit.

If the current is not  flowing in the electric circuit then it is said to be open electric circuit.

Therefore, a complete path through which charge can flow is an electric circuit.

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vladimir1956 [14]
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Sorry I was only able to answer a few questions, but I hope these few answers help! :) 
4 0
3 years ago
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A _ system is one in which one subsystem provides services to another subsystem.
astra-53 [7]

Answer:

u

Explanation:

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2 years ago
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Humans have three types of cone cells in their eyes, which are responsible for color vision. Each type absorbs a certain part of
xxMikexx [17]

Answer:

Frequency of the light will be equal to 6.97\times 10^{1}Hz

Explanation:

We have given wavelength of the light \lambda =430nm=430\times 10^{-9}m

Velocity of light is equal to v=3\times 10^8m/sec

We have to find the frequency of light

We know that velocity is equal to v=\lambda f, here \lambda is wavelength and f is frequency of light

So frequency of light will be equal to f=\frac{v}{\lambda }=\frac{3\times 10^8}{430\times 10^{-9}}=6.97\times 10^{1}Hz

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5 0
3 years ago
By calculating its wavelength (in nm), show that the second line in the Lyman series is UV radiation.
Rashid [163]

Answer:

 λ = 102.78  nm

This radiation is in the UV range,

Explanation:

Bohr's atomic model for the hydrogen atom states that the energy is

           E = - 13.606 / n²

where 13.606 eV   is the ground state energy and n is an integer

an atom transition is the jump of an electron from an initial state to a final state of lesser emergy

            ΔE = 13.606 (1 / n_{f}^{2} - 1 / n_{i}^{2})

the so-called Lyman series occurs when the final state nf = 1, so the second line occurs when ni = 3, let's calculate the energy of the emitted photon

            DE = 13.606 (1/1 - 1/3²)

            DE = 12.094 eV

let's reduce the energy to the SI system

            DE = 12.094 eV (1.6 10⁻¹⁹ J / 1 ev) = 10.35 10⁻¹⁹ J

let's find the wavelength is this energy, let's use Planck's equation to find the frequency

            E = h f

             f = E / h

            f = 19.35 10⁻¹⁹ / 6.63 10⁻³⁴

            f = 2.9186 10¹⁵ Hz

now we can look up the wavelength

           c = λ f

           λ = c / f

           λ = 3 10⁸ / 2.9186 10¹⁵

           λ = 1.0278  10⁻⁷ m

let's reduce to nm

            λ = 102.78  nm

This radiation is in the UV range, which occurs for wavelengths less than 400 nm.

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3 years ago
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4 0
3 years ago
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