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8_murik_8 [283]
3 years ago
7

Why solids do not undergo diffusion​

Chemistry
1 answer:
babunello [35]3 years ago
4 0

Answer:

<em>Solids</em><em> </em><em>do</em><em> </em><em>not</em><em> </em><em>undergo</em><em> </em><em>diffusion</em><em> </em><em>because</em><em> </em><em>it</em><em> </em><em>has</em><em> </em><em>a</em><em> </em><em>fixed</em><em> </em><em>structure</em><em> </em><em>(</em><em>vibrates</em><em> </em><em>in</em><em> </em><em>a</em><em> </em><em>fixed</em><em> </em><em>position</em><em>)</em><em> </em><em>and</em><em> </em><em>it</em><em> </em><em>also</em><em> </em><em>cannot</em><em> </em><em>be</em><em> </em><em>compressed</em><em>.</em><em> </em>

<em>Hoped</em><em> </em><em>this</em><em> </em><em>helped</em><em> </em><em>in</em><em> </em><em>any</em><em> </em><em>way</em><em> </em>

<em>Have</em><em> </em><em>a</em><em> </em><em>nice</em><em> </em><em>day</em><em> </em>

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First, we have to get:

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when m is the mass of ice = mol * molar mass

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by substitution:

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q3 = m*C*ΔT

when m is the mass of water = 18 g 

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</span><span>Rutherford had found the positively charged nucleus in the middle of every atom using his Gold Foil Experiment. While doing this experiment, he expected these particles to just pass right through the foil but they bounced right back. He also proposed there were negatively charged electrons revolving around the nucleus.
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If you have 10 grams of Lithium Oxide what will the volume be? Show your work
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Answer:

Volume occupied by 10 grams of Lithium Oxide at STP is 7.52 L

Explanation:

STP (Standard Temperature and Pressure) : It is used while performing calculation on gases and provide standards of measurements while performing experiment.

According to IUPAC (International Union of Pure And applied Chemistry) , standard temperature is 273.15 K and Pressure is 100 kPa (0.9869 atm). At STP condition 1 mole of substance occupies 22.4 L volume .

Molar mass of Lithium Oxide = 29.8 g/mol

Li_{2}O = 2(6.9) + 15.99 = 29.8

Mass of 1 mole Li_{2}O = 29.8 g

1 mole Li_{2}O occupies, Volume = 22.4 L

29.8 g Li_{2}O occupies, V = 22.4 L

1 g Li_{2}O occupies ,V = \frac{22.4}{29.8}

1 g Li_{2}O occupies ,V = 0.7516 L

10 g tex]Li_{2}O[/tex] occupies ,V = 0.7516 \times10 L

V = 7.52 L

So, volume occupied by Lithium Oxide At STP is 7.52 L

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