Answer:
0.1 mol
Explanation:
Step 1: Given data
- Volume of the solution of sodium hydroxide (V): 200 cm³
- Molar concentration of sodium hydroxide (C): 0.5 mol/dm³
Step 2: Convert "V" to dm³
We will use the conversion factor 1 dm³ = 1000 cm³.
200 cm³ × 1 dm³/1000 cm³ = 0.200 dm³
Step 3: Calculate the moles (n) of NaOH
The molarity of the NaOH solution is equal to the moles of NaOH divided by the volume of solution.
C = n/V
n = C × V
n = 0.5 mol/dm³ × 0.200 dm³ = 0.1 mol
Explanation:
The answer is thermal energy/ kinetic energy.. because friction on hands promotes thermal energy. because you want your hands 2 be warm, rubbing them 2gether creates heat and absorption of heat thru the skin which skin is susceptible to warm, humans can put hands under arm pits to warm hands, without any available heat source..
Explanation:
density can be calculated using the following rule: density=mass/volume
therefore,
mass = density x volume
we have density 8.9gm/cm³ and volume=3cm³ substituting in the above equation, we can calculate the mass as follows:
mass = 8.9 x 3 = 26.7 grams,
Approx 27 grams
D. all of these
Explanation:
All of given choices are the physical properties of the gold as given by the table.
Color is also a physical property.
Ionization potential and electronegativity are chemical properties of the metal.
The physical property of a substance tells us everything about a substance when no change is occurring to it.
Such properties are observed with our sense or instruments or pieces of apparatus.
- Examples are color of matter, state of matter, odor, taste, density, boiling point, melting point, solubility, hardness, texture etc
learn more:
Chemical properties brainly.com/question/2376134
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Answer:
a. 5.9 × 10⁻³ M/s
b. 0.012 M/s
Explanation:
Let's consider the following reaction.
2 N₂O(g) → 2 N₂(g) + O₂(g)
a.
Time (t): 12.0 s
Δn(O₂): 1.7 × 10⁻² mol
Volume (V): 0.240 L
We can find the average rate of the reaction over this time interval using the following expression.
r = Δn(O₂) / V × t
r = 1.7 × 10⁻² mol / 0.240 L × 12.0 s
r = 5.9 × 10⁻³ M/s
b. The molar ratio of N₂O to O₂ is 2:1. The rate of change of N₂O is:
5.9 × 10⁻³ mol O₂/L.s × (2 mol N₂O/1 mol O₂) = 0.012 M/s