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In-s [12.5K]
3 years ago
7

What is the definition of light of one year ?​

Physics
2 answers:
Elodia [21]3 years ago
8 0

Answer:

The definition of a light year is the distance a photon will travel in a year in a vaccume, like space.

Lesechka [4]3 years ago
8 0
A unit of astronomical distance equivalent to the distance that light travels in one year
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Two particles with masses m and 3m are moving toward each other along the x axis with the same initial speeds Vi. Particle m is
nignag [31]

Answer:

v1 = \sqrt{(2)}Vi

v2 = \sqrt{(2/3)}Vi

ANGLE is 35.3 degree celcius

Explanation:

Given data:

mass m and 3m

initial speed Vi

particle with mass m is moving toward left while particle with mass 3m is moving toward right

By using conservation of momentum :

mVi + 3m(-Vi) = mv1 +3mv2

-2mVi = m(v1 + 3v2)

-2Vi = v1 + 3v2

conservation of energy :

m(Vi^2) + 3m(-Vi^2) = mv1^2 + 3mv2^2

4mVi^2 = m(v1^2+3v2^2)

4Vi^2 = v1^2+3v2^2

After collision, particle with mass m moves at right angles, thus by considering conservation of momentum in x & y direction,

x direction : -2mVi = 3m.v2i

-2Vi = 3v2i

y direction : 0 = m(v1)j+3m(v2)j

-v1j = 3v2j

subsitute these value in energy conservation

v1 = \sqrt{(2)}Vi

v2 = \sqrt{(2/3)}Vi

angle = tan^{-1}(\frac{\sqrt{(2)}}{2}) =35.3 degree from x-axis

8 0
2 years ago
consider the free-body diagram. if you want the box to move, the force applied while dragging must be greater than the
NeTakaya

Answer:

Force of static friction between the two surfaces

Explanation:

When two surfaces come into contact, they exert a force that resist the sliding of the two surfaces. This force is called static friction.

This force is given by the relation

                                       F_{s}=\mu_{s}\eta

Where,

                             μ - coefficient of static friction

                             η - normal force acting on the body

When a force acts on a body placed on a rough surface, it doesn't do any work if the applied force was less than the force of static friction.

So, in order to move the body, the applied force should be greater than the force of static friction.

6 0
2 years ago
2. An object with moment of inertia ????1 = 9.7 x 10−4 kg ∙ m2 rotates at a speed of 3.0 rev/s. A 20 g mass with moment of inert
svetoff [14.1K]

Answer:

2.85 rad/s

Explanation:

5 cm = 0.05 m

20 g = 0.02 kg

When dropping the 2nd object at a distance of 0.05 m from the center of mass, its corrected moments of inertia is:

I_2 = 1.32\times10^{−6} + 0.02 * 0.05^2 = 0.513\times10^{-4} kgm^2

So the total moment of inertia of the system of 2 objects after the drop is:

I = I_1 + I_2 = 9.7\times10^{-4} + 0.513\times10^{-4} = 0.0010213 kgm^2

From here we can apply the law of angular momentum conservation to calculate the post angular speed

\omega_1 I_1 = \omega_2 I

\omega_2 = \omega_1 \frac{I_1}{I} = 3 \frac{9.7\times10^{-4}}{0.0010213} = 2.85 rad/s

6 0
3 years ago
The total mass of the wheelbarrow and the road is 80 kg calculate the weight of the wheelbarrow and the road
Alja [10]

Answer:

The weight of the wheelbarrow and the road is 784 N and the force required to lift the wheelbarrow is 784 N.

Explanation:

Given that,

The total mass of the wheelbarrow and the road is 80 kg.

The weight of an object is given by :

W = mg

where

g is acceleration due to gravity

So,

W = 80 × 9.8

= 784 N

So, the force required to lift the wheelbarrow is equal to its weight i.e. 784 N.

7 0
3 years ago
Two forces act in opposite directions on a wood block. What will happen if the forces are unbalanced?
worty [1.4K]

Answer:

D

Explanation:

If two unequal forces act in opposite directions, one larger force must cancel out the smaller force,

leaving the net force to be some number in one direction.

Take for example a game of tug-of-war; there are two  OPPOSITE forces (groups of people) acting on the rope, one force is pulling with a force in the negative direction while the other force is pulling in the positive direction.

If the forces on the rope were unequal, then the stronger force (group) will pull everything in their direction.

The same will happen on two unequal forces of opposite directions acting on a wooden block. Therefore, since the resultant force will have a non-zero magnitude and direction, there will be a change in the block's motion and position.

7 0
2 years ago
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