Sulfur-32 Information
This element is absorbed by plants from the soil as sulphate ion. Sulfur has 23 isotopes, 4 of them are stable. Sulfur is used in matches, gunpowder, medicines, rubber and pesticides, dyes and insecticides.
<h3>Which isotope of sulfur contributes the least to its mass number?</h3>
Sulfur (16S) has 23 known isotopes with mass numbers ranging from 27 to 49, four of which are stable: 32S (95.02%), 33S (0.75%), 34S (4.21%), and 36S (0.02%).
<h3>What is the use of Sulphur 35 isotope?</h3>
A radioactive sulfur isotope; a beta emitter with a half-life of 87.2 days; used as a tracer in the study of the metabolism of cysteine, cystine, methionine, and other compounds; also used to estimate, with labeled sulfate, extracellular fluid volumes.
Learn more about isotopes here:
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brainly.com/question/364529</h3><h3 /><h3>#SPJ4</h3>
- 3.5
- 9
- 24.7
- 8.01
- 0.006
- 13(1.25×1012=12.65)
Explanation:
Above we have simply looked the condition that where we put decimal point that gives your needed answer after round off.
For example:
we have to make 2 s.f from 345 so we kept decimal after 3 and we rounded off to make 3.5 from 3.45
Hope you got it
Answer:
Hello, Im Mack. Hope you're doing well. :)
Here is my Correct, custom answer for the lab Question, (I also took the same assignment and got a 100% score)
Explanation:
The heating of the sodium acetate solution made it change from super-saturated to un-saturated. Yet now that it cooled back to room temperature Im sure it is saturated. it wasn't able to disolve the excess sodium acetate left over at room temperature and had to be heated so now that it is back to room temperature I Think it will not disolve the sodium acetate left in the solution until it is heated again.
Hope this helped you out,
Please feel free to comment for further help, and I'll reply asap.
<u>Have a great day my friend :)</u>
Answer:
The given statement is true.
Explanation:
Initially, the addition of borane to the alkene takes place in the form of a concerted reaction owing to the dissociation of the bond and subsequent formation, which occurs at a similar time. After that the Anti Markovnikov supplementation of boron takes place. The addition of this atom takes place with the less substituted carbon of the alkene that then substitutes the molecule of hydrogen on the more substituted carbon.
Then through the donation of a pair of electrons from the hydrogen peroxide ion, the process of oxidation takes place resulting in the formation of trialkylborane. After this realignment of an R group with its pair of bonding, electrons take place with adjacent oxygen resulting in the withdrawal of a hydroxide ion. Eventually, the trialkylborate reacts with the aqueous NaOH to generate alcohol and sodium borate as the side product.