If the pressure of a gas is 2.43 atm what is it’s pressure in kpa

You have 7.86 x 10^23 molecules of NaCl. This would be equal to ___ grams of NaCl.

sergij07 [2.7K]

$7.86 \times 10 {}^{23} atoms \\ \frac{7.86}{6.022} \times \frac{10 {}^{23} }{ {10}^{23} } = 1.305\: moles$

1.305 × (23+35.5) = 76.34 grams

3 0

2 years ago

Soil is a renewable resource if properly maintained. Which of the following helps to maintain healthy soil?

brilliants [131]

C. crop rotation

Explanation:

Crop rotation is a farming practice that is commonly used to maintain a healthy soil.

This practices helps to conserve and appropriate a soil for the best use.

During crop rotation, different crop species are planted during a growing season. The patterns are designed to cultivate both crops that replenish and deplete the nutrients in soil.

Through this the fertility of the soil is sustained all year round.

This helps to avoid the use of pesticides on crops.

learn more:

Regions in Mexico for growing crops brainly.com/question/1472033

#learnwithBrainly

8 0

3 years ago

A group of electrons orbiting at roughly the same distance from the nucleus

REY [17]

A shell of electrons.

6 0

3 years ago

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Sulfuric acid is commonly used as an electrolyte in car batteries. Suppose you spill some on your garage floor. Before cleaning

Neporo4naja [7]

Answer:

The mass of NaHCO3 required is 235.22 g

Explanation:

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Continuation of Question:

2NaHCO3(s) + H2SO4(aq) → Na2SO4(aq) + 2CO2(g) + 2H2O(l)

You estimate that your acid spill contains about 1.4 mol H2SO4. What mass of NaHCO3 do you need to neutralize the acid?

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The question requires us to calculate the mass of NaHCO3 to neutralize the acid.

From the balanced chemical equation;

1 mol of H2SO4 requires 2 mol of NaHCO3

1.4 would require x?

Upon solving for x we have;

x = 1.4 * 2 = 2.8 mol of NaHCO3

The relationship between mass and number of moles is given as;

Mass = Number of moles * Molar mass

Mass = 2.8 mol * 84.007 g/mol

Mass = 235.22 g

3 0

3 years ago

Substance ΔG°f(kJ/mol) M3O4(s) −8.80 M(s) 0 O2(g) 0 Consider the decomposition of a metal oxide to its elements, where M represe

baherus [9]

Answer:

The equilibrium constant is $K =0.02867$

The equilibrium pressure for oxygen gas is $P_{O_2} = 0.09367\ atm$

Explanation:

From the question we are told that

The equation of the chemical reaction is

$M_2 O_3 _{(s)} ----> 2M_{(s)} + \frac{3}{2} O_2_{(g)}$

The Gibbs free energy for $M_3 O_4_{(s)}$ is $\Delta G^o_{1} = -8.80 \ kJ/mol$

The Gibbs free energy for $M{(s)}$ is $\Delta G^o_{2} = 0 \ kJ/mol$

The Gibbs free energy for $O_2{(s)}$ is $\Delta G^o_{3} = 0 \ kJ/mol$

The Gibbs free energy of the reaction is mathematically represented as

$\Delta G^o_{re} = \sum \Delta G^o _p - \sum G^o _r$

$\Delta G^o_{re} = \sum \Delta G^o _1 - \sum( G^o _2 +G^o _3)$

Substituting values

From the balanced equation

$\Delta G^o_{re} =[ (2 * 0) + (\frac{3}{2} * 0 )] - [1 * - 8.80]$

$\Delta G^o_{re} = 8.80 kJ/mol =8800J/mol$

The Gibbs free energy of the reaction can also be represented mathematically as

$\Delta G^o_{re} = -RTln K$

Where R is the gas constant with a value of $R = 8.314 J/mol \cdot K$

T is the temperature with a given value of $T = 298 K$

K is the equilibrium constant

Now equilibrium constant for a reaction that contain gas is usually expressed in term of the partial pressure of the reactant and products that a gaseous in state

The equilibrium constant for this chemical reaction is mathematically represented as

$K_p =[ P_{O_2}]^{\frac{3}{2} }$