3 years ago

PLEASE HELP it takes tsooo long! lol ima fail! please help! thanks!

Physics

2 answers:

sp2606 [1]3 years ago

7 0

B and C are the ones.

Natasha_Volkova [10]3 years ago

4 0

Answer:

A and c, hope i helped xx

Explanation:

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2 years ago

michael kicks a ball at an angle if 36* horizontal. its initial velocity is 46 m/s. Find the maximum height it can reach, total

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(a) At its maximum height, the ball's vertical velocity is 0. Recall that

${v_y}^2-{v_{0y}}^2=2a_y\Delta y$

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$-\left(\left(46\,\dfrac{\mathrm m}{\mathrm s}\right)\sin36^\circ\right)^2=2\left(-9.8\,\dfrac{\mathrm m}{\mathrm s^2}\right)y_{\mathrm{max}}$

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(b) The time the ball spends in the air is twice the time it takes for the ball to reach its maximum height. The ball's vertical velocity is

$v_y=v_{0y}+a_yt$

and at its maximum height, $v_y=0$ so that

$0=\left(46\,\dfrac{\mathrm m}{\mathrm s}\right)\sin36^\circ+\left(-9.8\,\dfrac{\mathrm m}{\mathrm s}\right)t$

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which would mean the ball spends a total of about 5.6 seconds in the air.

$x=v_{0x}t$

so that after 5.6 seconds, it will have traversed a displacement of

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2 years ago