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Masteriza [31]
4 years ago
8

PLEASE HELP it takes tsooo long! lol ima fail! please help! thanks!

Physics
2 answers:
sp2606 [1]4 years ago
7 0

B and C are the ones.

Natasha_Volkova [10]4 years ago
4 0

Answer:

A and c, hope i helped xx

Explanation:

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a boat sailing against the current experiences an acceleration of -11 m/s^2 if the boats initial velocity is 44 m/s upstream, ho
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Answer:4s

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3 years ago
Find the average velocity of the car during the time last three second interval. Answer in units of m/s.
Pani-rosa [81]

Answer:

<u>Average Velocity:</u>

When a body covers some displacement moving from point A to B, in a given time,t. Then dividing the total distance covered by the time taken to complete the displacement is called as the average velocity of that car.

We can calculate the average velocity of car by subtracting the initial displacement of a body,s₁ from  the final displacement position of the body, s₂. And then dividing by the initial time,t₁ been subtracted from the final time,t₂.

  • Δv=x₂-x₁/t₂-t₁,

We will get the required results, now if we want to obtain the results in the final three seconds then, we can have the following explanation to that as given.

Explanation:

Lets say, that we have the car moving for 10 seconds and then it stops at the eleventh second of the trip on final position, of the displacement. Then we divide the whole trips into small segments, as we will have the different velocity at each interval but, the velocity is unknown at the last 3 seconds is unknown=?.  

  • Total time taken, Δt= 11 seconds,
  • Then lets say the velocity at the 8th second is , v=25 m/s,then
  • Δv=x₂-(25)/11-0,⇒Δv=x₂-25/11,
3 0
3 years ago
What is another name for constructive interference?
SOVA2 [1]
C I hope this help bud
4 0
3 years ago
If the distance separating the objects is the same for each pair which pair will have the greatest gravitational force between T
hjlf

Answer:

ur 2 sqyares out of the cicle. how many squares to get back in for example.

Explanation:

7 0
3 years ago
a 2.6 kg block is attached to a horizontal spring that has a spring constant of 126 N/m. At the instant when the displacement of
NeTakaya

Answer:

The acceleration of the object is 5.57\ m/s^2.

Explanation:

Given that,

Mass of the block, m = 2.6 kg

Spring constant of the spring, k = 126 N/m

At the instant when the displacement of the spring from its unstained length is 0.115 m. We need to find the acceleration of the object.

When the block is displaced, the force acting on the spring is equal to the force due to its motion. Such as :

kx=ma

a is acceleration of the object

a=\dfrac{kx}{m}\\\\a=\dfrac{126\times 0.115}{2.6}\\\\a=5.57\ m/s^2

So, the acceleration of the object is 5.57\ m/s^2.

8 0
3 years ago
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