Answer:
See explanation
Explanation:
Mass of mixture of fluorene and benzoic acid = 558 mg
Mass of pure fluorene after purification = 185 mg of fluorene
Mass of pure benzoic acid after purification = 144 mg of benzoic acid
Percentage of fluorene int he mixture = 185mg/558mg * 100 = 33.15 %
Percentage of benzoic acid in the mixture = 144mg/558mg * 100 = 25.81 %
Percentage of impurities = 100% - [33.15 + 25.81]
Percentage of impurities = 100 - 58.96
Percentage of impurities = 41.04 %
<h2>suspension should be correct
</h2>
<u>a suspension </u>
<em>the particles are big enough to settle </em>
<em>
</em>
<u>a colloid</u>
<em>the particles are too small to ever settle
</em>
<u>a solution
</u>
<em>homogeneous mixture of two or more substances</em>
If 1.2 L of solution contains 0.97 mol
then let 1 L of solution contain x mol
⇒ (1.2 L) x = (0.97 mol) (1 L)
x = (0.97 mol · L) ÷ (1.2 L)
x = 0.8083 mol
Thus the molarity of the Barium Chloride solution is 0.808 mol / L OR 0.808 mol/dm³.
It depends on where your yields sign is, but usually it's the elements/ compounds in the front. In this case, HCL and NaOH
