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Temka [501]
3 years ago
9

What product(s) are formed during this chemical reaction? (There will be two correct answers)

Chemistry
1 answer:
Zinaida [17]3 years ago
4 0

Answer:

Ca3(PO4)2 and Na

Explanation:

The reaction equation is;

3Ca + 2Na3PO3 -------> Ca3(PO3)2 + 6Na

We must remember that calcium is above sodium in the electrochemical series. This implies that calcium can displace sodium from its solution. Calcium has a reduction potential of -2.87 V while sodium has a reduction potential of -2.71 V. The ion with the more negative reduction potential can easily displace the other in aqueous solution.

This explains why the reaction above is possible.

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What do all four animals have in common? cat worm spider crab
Free_Kalibri [48]
<span>They are composed of cells</span>
4 0
3 years ago
34. Explain how dimensional analysis is used to solve<br> problems.
alisha [4.7K]

Answer: By understanding conversion factors and how they are related to each other

Explanation:

Dimensional Analysis is a step by step approach to solving problems in Physics, Chemistry , and Mathematics. It involves having a clear knowledge and understanding to be able to convert a given unit to another in the same dimension using  conversion factors and knowing how they are related to each other.

For instance, In Chemistry, we want to Convert 120mL to L.(note that ml stands for millilitres and ;L stands for litres)

Or first approach will be to write out the conversion factor related to our problem which is

1000ml =1L

such that 120ml = (we cross multiply))

giving us  120ml x 1L/1000ml =0.12L

This same process is applied to convert any type of dimensional analysis problems be it physics or mathematics.

7 0
3 years ago
If three molecules of hydrogen react with one molecule of nitrogen, how many molecules of ammonia would be formed?
joja [24]

Answer:

The answer to your question is 2 molecules, or B(edg 2021).

Explanation:

edg 2021

8 0
3 years ago
Rank these acids according to their expected pKa values.
givi [52]

Answer:

According to their expected pKa values, the order of those acids should be:

1- Cl2CHCOOH is the strongest acid and the lowest pKa.

2- ClCH2COOH is a strong acid, but no more than the first. Medium pKa value.

3- ClCH2CH2COOH is a strong acid, but no more than the two previous acids. High pKa value.

4- CH3CH2COOH  is the weakest acid, so the highest pKa value.

Explanation:

The pKa values are the negative logarithm of dissociation constant. It represents the relative strengths of the acids. Stronger acids show smaller pKa values and weak acids present larger pKa value. The stronger the acid, the weaker it's the conjugate base. The larger the pKa of the conjugate base, the stronger the acid. The strength of an acid is inversely related to the strength of its conjugate.

Conjugate bases are the substance that has one less proton than the parent acid. The conjugate base of the acid presented in the problem are:

ClCH2COOH -> ClCH2COO-  + H+

ClCH2CH2COOH -> ClCH2CH2COO- + H+

CH3CH2COOH -> CH3CH2COO- + H+

Cl2CHCOOH -> Cl2CHCOO - + H+

Cl2CHCOOH. The negative charge presented on its conjugate base is by resonance and inductive effect. This is the strongest acid.

ClCH2COOH. A negative charge is stabilized by resonance and electron-withdrawing but only one atom is present. So this acid is less strong than the first one.

ClCH2CH2COOH. The negative charge is stabilized by resonance and electron-withdrawing atom but the effect is less compared to the two acids showed previously.

CH3CH2COOH. The negative charge is stabilized by resonance and destabilized due to CH3 group. This is the weakest acid among the problem.

Stronger acids have smaller pKa values and weak acids have larger pKa values. Due to the information present in this problem, Cl2CHCOOH is the strongest acid and the lowest pKa. CH3CH2COOH is the weakest acid, so the highest pKa value.

Finally, we can conclude that according to their expected pKa values, the order of those acids should be:

1- Cl2CHCOOH is the strongest acid and the lowest pKa.

2- ClCH2COOH is a strong acid, but no more than the first. Medium pKa value.

3- ClCH2CH2COOH is a strong acid, but no more than the two previous acids. High pKa value.

4- CH3CH2COOH  is the weakest acid, so the highest pKa value.

3 0
3 years ago
What isapplied in case where the base is not a OH donator
blagie [28]
It will received an H+. I’m not sure if that answers your question correctly
8 0
3 years ago
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