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2 years ago

What is the mass of .550 mL of alcohol (density = 82.0 g/mL)

Chemistry

2 answers:

Fynjy0 [20]2 years ago

6 0

45.1 ml of alcohol. Multiply 82 by .55 because it’s less than 1 ml

Aleks04 [339]2 years ago

4 0

Answer:

1.223 g/ml

Explanation:

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Can you see a non living and living atoms with a magnifying glass ??

WARRIOR [948]

Answer:

Explanation:

you would need an electron microscope to see atoms.

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3 years ago

What is the oxidation number of carbon in the compound carbon dioxide, CO2?

IRISSAK [1]

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2 years ago

Which of the following chemical formulas is a compound? a. Ne b. NaCl c. Cu d. C

qaws [65]

NaCl beacuse it has 2 elements combined

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3 years ago

Read 2 more answers

In reality, a hydrate of iron(III) nitrate had to be used, not the anhydrous salt. As you may guess, some of the hydrate’s mass

liq [111]

Answer: The mass of nonahydrate iron (III) nitrate is 16.2 g

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of $Fe(NO_3)_3$ = 0.0020 M

Volume of solution = 2 L

Putting values in above equation, we get:

$0.0200M=\frac{\text{Moles of }Fe(NO_3)_3}{2L}\\\\\text{Moles of }Fe(NO_3)_3=(0.0200mol/L\times 2L)=0.04mol$

The chemical equation for the decomposition of hydrated iron (III) nitrate follows:

$Fe(NO_3)_3.9H_2O\rightarrow Fe(NO_3)_3+9H_2O$

By Stoichiometry of the reaction:

1 mole of iron (III) nitrate is produced from 1 mole of hydrated iron (III) nitrate

So, 0.04 moles of iron (III) nitrate will be produced from = $\frac{1}{1}\times 0.04=0.04mol$ of hydrated iron (III) nitrate

To calculate the mass from given number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Molar mass of nonahydrate iron (III) nitrate = 404.0 g/mol

Moles of nonahydrate iron (III) nitrate = 0.04 moles

Putting values in above equation, we get:

$0.04mol=\frac{\text{Mass of nonahydrate iron (III) nitrate}}{404.0g/mol}\\\\\text{Mass of nonahydrate iron (III) nitrate}=(0.04mol\times 404.0g/mol)=16.2g$

Hence, the mass of nonahydrate iron (III) nitrate is 16.2 g

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2 years ago

If a body does not have enough potassium, how might that affect neuronal firing?

astraxan [27]

Potassium is fundamental for neuron activity. If a body does not have enough potassium, then the neuron will struggle to fire because there will not be enough positively charged ions to trigger the firing of the neuron.

The potassium (K+) is maintained at a high level within the neuron at rest, whereas sodium (Na+) is maintained at a high level outside of the cell.

Neurons contain K+ and Na+ leakage channels that allow the two ions to diffuse in favor of a concentration gradient.

Depolarization opens both K+ and Na+ channels in the membrane, thereby these ions can flow out and into the axon, respectively.

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2 years ago