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alisha [4.7K]
3 years ago
6

What is the mass of .550 mL of alcohol (density = 82.0 g/mL)

Chemistry
2 answers:
Fynjy0 [20]3 years ago
6 0
45.1 ml of alcohol. Multiply 82 by .55 because it’s less than 1 ml
Aleks04 [339]3 years ago
4 0

Answer:

1.223 g/ml

Explanation:

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While performing the Acid-catalyzed Hydrolysis of Epoxides experiment you used a solution containing 1.84 mL of cyclohexene oxid
Elenna [48]

Answer:

The moles of starting material is 1.8212 \times 10^{-2} mole

Explanation:

Given:

Cyclohexene oxide material is used

Density = 0.97\frac{g}{mL}

Volume = 1.84  mL

Formula of Cyclohexene oxide = C_{6} H_{10} O

Molar mass is given by,

C = 6 \times 12 = 72

H = 10 \times 1 = 10

O = 1 \times 16 = 16

⇒ m' = 96\frac{g}{mol}

Mass m = 0.97 \times 1.84 = 1.7848 g

Moles is given by,

  n = \frac{m}{m'}

  n = \frac{1.7848}{98}

  n = 1.8212 \times 10^{-2} mol

Therefore, the moles of starting material is 1.8212 \times 10^{-2} mole

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3 years ago
Only animals and not plants can adapt to their environment true or false
Vladimir79 [104]

Answer:

true

Explanation:

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3 0
3 years ago
The refining of aluminum from bauxite ore (which contains 50.% Al2O3 by mass) proceeds by the overall reaction 2Al2O3 + 3C → 4Al
iragen [17]

Answer:

18.9 x 10¹³ grams of Bauxite Ore

Explanation:

Al₂O₃ = 50% of Bauxite Ore

Al₂O₃ = 0.5 (Bauxite Ore)--------------------------------------- (1)

Overall reaction:

2Al₂O₃ + 3C → 4Al + 3CO₂--------------------------------------- (2)

[ Al= 27 , O=16, C=12]

From  (2), 2 moles of  Aluminium oxide (Al₂O₃) gives  4 moles of Aluminium

In terms of grams, we can say:

Al₂O₃ = [2(27) +3(16)]

         = 54 +48

         =102grams

2 moles of Al₂O₃ = 2 x102grams

                            =204grams

4 moles of Al = 4 x 27

                      =108 grams

So from (2):

204 grams of  Al₂O₃   = 108 grams of  Aluminium

x grams of  Al₂O₃        =  5.0 x 10¹³grams of Aluminium

Calculating for x:

x =  (204 x  5.0 x 10¹³)/ 108

  = 9.44 x 10¹³ grams

So 9.44 x 10¹³ grams of pure bauxite (Bauxite) is required.

However the to calculate the quantity of raw bauxite, we use (1):

Bauxite ore = Pure Bauxite/0.5

                   =   9.44 x 10¹³ grams/0.5

                   =   18.88 x 10¹³ grams

                    ≈ 18.9 x 10¹³ grams

 

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3 years ago
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Answer:

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2 years ago
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Damian mixed two samples together: a
lesantik [10]

Answer:C

Explanation:

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2 years ago
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