Answer:
Theres quadrants so -3,9 would be lower about III
6,-6 would be IV
0,-1 1/2 That would be near the 0 obviously so II
Answer:
3
Step-by-step explanation:
We have a system with two equations, one equation is a quadratic function and the other equation is a linear function.
To solve this system we have to clear "y" in both equations, and then equal both equations, then we will have a quadratic function and equal it to zero:

Then to resolve a quadratic equation we apply Bhaskara's formula:


It usually has two solutions.
But it could happen that
then the equation doesn't have real solutions.
Or it could happen that there's only one solution, this happen when the linear equation touches the quadratic equation in one point.
And it's not possible to have more than 2 solutions. Then the answer ir 3.
For example:
In the three graphs the pink one is a quadratic function and the green one is a linear function.
In the first graph we can see that the linear function intersects the quadratic function in two points, then there are two solutions.
In the second graph we can see that the linear function intersects the quadratic function in only one point, then there is one solutions.
In the third graph we can see that the linear function doesn't intersect the quadratic function, then there aren't real solutions.
Step-by-step explanation:
5x + 2y = 10
Ax + By = C
A = 5
B = 2
C = 10
Answer:
SUMMARY:
→ Not a Polynomial
→ A Polynomial
→ A Polynomial
→ Not a Polynomial
→ A Polynomial
→ Not a Polynomial
Step-by-step explanation:
The algebraic expressions are said to be the polynomials in one variable which consist of terms in the form
.
Here:
= non-negative integer
= is a real number (also the the coefficient of the term).
Lets check whether the Algebraic Expression are polynomials or not.
Given the expression

If an algebraic expression contains a radical in it then it isn’t a polynomial. In the given algebraic expression contains
, so it is not a polynomial.
Also it contains the term
which can be written as
, meaning this algebraic expression really has a negative exponent in it which is not allowed. Therefore, the expression
is not a polynomial.
Given the expression

This algebraic expression is a polynomial. The degree of a polynomial in one variable is considered to be the largest power in the polynomial. Therefore, the algebraic expression is a polynomial is a polynomial with degree 5.
Given the expression

in a polynomial with a degree 4. Notice, the coefficient of the term can be in radical. No issue!
Given the expression

is not a polynomial because algebraic expression contains a radical in it.
Given the expression

a polynomial with a degree 3. As it does not violate any condition as mentioned above.
Given the expression


Therefore, is not a polynomial because algebraic expression really has a negative exponent in it which is not allowed.
SUMMARY:
→ Not a Polynomial
→ A Polynomial
→ A Polynomial
→ Not a Polynomial
→ A Polynomial
→ Not a Polynomial