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Akimi4 [234]
3 years ago
12

Complete combustion of 7.50 g of a hydrocarbon produced 23.1 g of CO2 and 10.6 g of H2O. What is the empirical formula for the h

ydrocarbon ?
Chemistry
2 answers:
r-ruslan [8.4K]3 years ago
7 0
A CH compound is combusted to produce CO2 and H2O 
CnHm + O2 -----> CO2 + H2O 
Mass of CO2 = 23.1g
 Mass of H2O = 10.6g
 Calculate by mass of the compounds
 For Carbon C, divide by molecular weight of CO2 and multiply with Carbon
molecular weight. So C in grams = 23.1 x (12.01 / 44.01) = 6.3 g C
 For Hydrogen H, divide by molecular weight of H2O and multiply with Hydrogen molecular weight. So H in grams = 10.6 x (2.01 / 18.01) = 0.53 g C
= 1.18 of H
 Calculate the moles for C and H
 6.3 grams of C x (1 mole/12.01 g C) = 0.524 moles of C
 1.18 grams of H x (1 mole/1.008 g H) = 1.17 moles of H
 Divides by both mole entities with smallest
 C = 0.524 / 0.524 = 1 x 4 = 4
 H = 1.17 / 0.524 = 2.23 x 4 = 10
 The empirical formula is C4H10.
steposvetlana [31]3 years ago
7 0
Chemical reaction: CₓHₐ + O₂ → xCO₂ + a/2H₂O.
m(CₓHₐ) = 7,50 g.
m(CO₂) = 23,1 g.
m(H₂O) = 10,6 g.
n(CO₂) = m(CO₂) ÷ M(CO₂).
n(CO₂) = 23,1 g ÷ 44 g/mol.
n(CO₂) = n(C) = 0,525 mol.
n(H₂O) = 10,6 g ÷ 18 g/mol = 0,588.
n(H₂O) : n(H) = 1 : 2.
n(H) = 1,176 mol.
n(H) : n(C) = 1,176 mol : 0,525 mol.
n(H) : n(C) = 2,25 : 1 /×4.
n(H) : n(C) = 9 : 4.
C₄H₉.
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0.67 mole/litre

Explanation:

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3 0
2 years ago
The hot dogs you ate at the barbecue last week were 75% fat-free by weight, had 275 calories, and weighed 110 g. a) What percent
vovangra [49]

Answer:

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c) 90%

Explanation:

a) 75% fat-free by weight means 25% of the weight is made by fat.

b) 110 g ___ 100%

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6 0
3 years ago
At 35.0°c and 3.00 atm pressure, a gas has a volume of 1.40 l. what pressure does the gas have at 0.00°c and a volume of 0.950 l
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Answer : The pressure of gas will be, 3.918 atm and the combined gas law is used for this problem.

Solution :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 3 atm

P_2 = final pressure of gas = ?

V_1 = initial volume of gas = 1.40 L

V_2 = final volume of gas = 0.950 L

T_1 = initial temperature of gas = 35^oC=273+35=308K

T_2 = final temperature of gas = 0^oC=273+0=273K

Now put all the given values in the above equation, we get the final pressure of gas.

\frac{3atm\times 1.40L}{308K}=\frac{P_2\times 0.950L}{273K}

P_2=3.918atm

Therefore, the pressure of gas will be, 3.918 atm and the combined gas law is used for this problem.

4 0
3 years ago
Read 2 more answers
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stiks02 [169]

The reaction between copper II chloride and sodium sulfide as well as lead II nitrate and potassium sulfate both produce precipitates.

The solubility of a substance in water is in accordance with the solubility rules.  It is possible that a solid product may be formed when two aqueous solutions are mixed together. That solid product is referred to as a precipitate.

Now, we will consider each reaction individually to decode whether or not a precipitate is possible.

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Learn more: brainly.com/question/11969651

6 0
3 years ago
How much heat in joules is required to heat a 43g sample of aluminum from an initial temperature of 72˚F to a final temperature
Stels [109]
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initial temperature: 72°F

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final temperature: 145°F
   
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Substituting to the equation,

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<em>Answer: 1574.82 J</em>
3 0
3 years ago
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