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Sergeeva-Olga [200]
3 years ago
11

Consider this balanced chemical equation: 5SF4 + 2I2O5 = 4IF5 + 5SO2 a. What is the limiting reagent when 4.687 grams SF4 reacts

with 6.281 grams I2O5 to produce IF5 and SO2.
Chemistry
1 answer:
Kaylis [27]3 years ago
7 0

Answer:

The limiting reagent is the SF₄

Explanation:

In order to determine the limiting reagent we convert the mass of the reactants to moles, and then, we work with stoichiometry.

4.687 g / 108.06 g/mol =  0.0433 moles of SF₄

6.281 g / 333.8 g/mol = 0.0188 moles of I₂O₅

The reaction is:  5SF₄ + 2I₂O₅ = 4IF₅ + 5SO₂

Ratio is 5:2. 5 moles of fluoride react with 2 moles of pentoxide

Then, 0.0433 moles of fluoride will react with (0.0433 . 2) / 5 = 0.0173 moles

We have 0.0188 moles of I₂O₅ and we need 0.0173 so there are some moles of pentoxide that remains after the reaction. In conclussion, the limiting reagent is the SF₄. We verify:

2 moles of pentoxide react with 5 moles of SF₄

Therefore, 0.0188 moles of I₂O₅ will react with (0.0188 . 5) / 2 = 0.0470 moles.

As we have 0.0433 moles of SF₄, we do not have enough moles.

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<h2>Answer :</h2><h3><u>QUESTION ①)</u></h3>

✔ C5H4 has a molecular molar mass of :

<em>M(C5H4) = 5 x M(C) + 4 x M(H) </em>

  • M(C5H4) = 5 x 12 + 4 x 1
  • M(C5H4) = 60 + 4
  • M(C5H4) = 64 g/mol

✔ The molecular mass of C5H4 is therefore 64 g/mol.

  • But, 128/64 = 2
<h3>This is double the molar mass of C5H4, this molecule has the formula 2C5H4.</h3>
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(12) Magnesium metal burns very brightly to produce heat and a white solid.
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Stoichiometry is best defined as the
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Stoichiometry is “quantitative relationship” among the “reactants” and the “products” in a “chemical reaction”.

<u>Explanation</u>:  

In stoichiometry “stoicheion” means element and “metron” means measure in Greek. The stoichiometric calculation depends upon “stoichiometric coefficients” in a “chemical equation” which can be explained as the “number of moles” of each substance (reactants or products). Stoichiometric calculation is done as follows:

For example reaction between nitrogen and hydrogen to form ammonia as

\mathrm{N}_{2}(\mathrm{g})+3 \mathrm{H}_{2}(\mathrm{g}) \longrightarrow 2 \mathrm{NH}_{3}(\mathrm{g})

Here stoichiometric coefficients show that “one molecule of nitrogen” reacts with “three molecules of hydrogen” to form “two molecules of ammonia”. Multiplying Avogadro number 6.022 \times 10^{23} to no of molecules in equation:

\text { For } \mathrm{N}_{2}: 1 \times 6.022 \times 10^{23}=1 \mathrm{mol}

\text { For } 3 \mathrm{H}_{2}: 3 \times 6.022 \times 10^{23}=3 \mathrm{mol}

\text { For } 2 \mathrm{NH}_{3}: 2 \times 6.022 \times 10^{23}=2 \mathrm{mol}

Taking molar masses into consideration:  

\text { For } \mathrm{N}_{2}: 1 \times 28.0=28.0 \mathrm{gm}

\text { For } 3 \mathrm{H}_{2}: 3 \times 2=6.0 \mathrm{gm}

\text { For } 2 \mathrm{NH}_{3}: 2 \times 17=34 \mathrm{gm}

Hence balanced equation gives stoichiometric coefficients which gives proportion by moles.

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harkovskaia [24]

Explanation:

Compounds are written with formulas showing which elements from the periodic table are combined. One very familiar compound is water. When two hydrogen atoms (H2) combine with one oxygen atom (O), it makes the compound H2O, which we know as water.

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How many grams is 2.25mol.of methane (CH)?
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Answer:  16.04246 grams

Explanation:

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