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Sergeeva-Olga [200]
3 years ago
11

Consider this balanced chemical equation: 5SF4 + 2I2O5 = 4IF5 + 5SO2 a. What is the limiting reagent when 4.687 grams SF4 reacts

with 6.281 grams I2O5 to produce IF5 and SO2.
Chemistry
1 answer:
Kaylis [27]3 years ago
7 0

Answer:

The limiting reagent is the SF₄

Explanation:

In order to determine the limiting reagent we convert the mass of the reactants to moles, and then, we work with stoichiometry.

4.687 g / 108.06 g/mol =  0.0433 moles of SF₄

6.281 g / 333.8 g/mol = 0.0188 moles of I₂O₅

The reaction is:  5SF₄ + 2I₂O₅ = 4IF₅ + 5SO₂

Ratio is 5:2. 5 moles of fluoride react with 2 moles of pentoxide

Then, 0.0433 moles of fluoride will react with (0.0433 . 2) / 5 = 0.0173 moles

We have 0.0188 moles of I₂O₅ and we need 0.0173 so there are some moles of pentoxide that remains after the reaction. In conclussion, the limiting reagent is the SF₄. We verify:

2 moles of pentoxide react with 5 moles of SF₄

Therefore, 0.0188 moles of I₂O₅ will react with (0.0188 . 5) / 2 = 0.0470 moles.

As we have 0.0433 moles of SF₄, we do not have enough moles.

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For the reaction N2O4(g) ⇋ 2NO2(g), Kc = 0.25 at 98°C. At a point during the reaction, the concentration of N2O4 = 0.50 M and th
Scilla [17]

Answer:

Q = 0.50

No

Left

Explanation:

At a generic reversible equation

aA + bB ⇄ cC + dD

The reaction coefficient (Q) is the ratio of the substances concentrations:

Q = \frac{[C]^c*[D]^d}{[A]^a*[B]^b}

Solids and liquid water are not considered in this calculus.

When the reaction achieves equilibrium (concentrations are constant), the Q value is named as Kc, which is the equilibrium constant of the reaction. If Q > Kc, it indicates that the concentration of the products is higher, so, the reaction must progress to the left and form more reactants; if Q < Kc, than the concentrations of the reactants, are higher, so, the reaction progress to the right.

In this case:

Q = \frac{[NO_2]^2}{[N_2O_4]}

Q = \frac{0.50^2}{0.50}

Q = 0.50

So, Q > Kc, the reaction is not at equilibrium and it progresses to the left.

6 0
3 years ago
The northern lights and huge power surges in technology are both effects of what
umka2103 [35]
Solar winds. Plasma particles from the sun affect earth's atmosphere and cause magnetic interferance.
7 0
3 years ago
A 250.0-ml sample of ammonia, nh3 (g), exerts a pressure of 833 torr at 42.4 °c. what mass of ammonia is in the container
Lelu [443]
To solve this, let's assume ideal gas behavior.

PV=nRT
Let's solve for n. Convert units to SI units first.

Pressure = 833 torr(101325 Pa/760 torr) = 111,057.53 Pa
Volume = 250 mL(1 L/1000 mL)(1 m³/1000 L) = 2.5×10⁻⁴ m³
Temperature = 42.4 + 273 = 315.4 K

n = (8,314 J/mol·K)(315.4 K)/(111057.53 Pa)(2.5×10⁻⁴ m³)
n = 94.45 mol

The molar mass of ammonia is 17.031 g/mol.
Mass = 94.45*17.031 = <em>1,608.51 g ammonia</em>


6 0
3 years ago
What mass of sucrose needs to be dissolved in 540 g of water in order to prepare a 15% by mass solution.
Lilit [14]

Answer:

95.3g

Explanation:

Given parameters:

Mass of water  = 540g

Percentage by mass of solution = 15%

Unknown:

Mass of sucrose = ?

Solution;

To solve this problem, we must understand that a solution is made up of solute dissolved in a solvent. A solute is the solid dissolved in another. The solvent is the is dissolving medium;

    Percentage by mass of solute in solution = \frac{Mass of solute}{Mass of solution}  x 100

Mass of solution  = mass of water + Mass of sucrose  = 540 + M

  where M is the mass of sucrose;

therefore;

                 \frac{M}{540 + M }  x 100   = 15

   Solving for M gives 95.3g

Mass of sucrose is 95.3g

5 0
2 years ago
Help me Guys please I need help with this My step sister is here and she's a demon and annoying Can I have good ideas what to do
Nesterboy [21]

Answer:

Lock her in the bathroom

Explanation:

3 0
2 years ago
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