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Valentin [98]
2 years ago
8

Mass data for reaction of NaHCO3-Na2CO3 mixture with HCL:

Chemistry
1 answer:
Zanzabum2 years ago
8 0
Is there a graph? I need to see a graph in order to help
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A certain man needed 400N of force to pull a load through a distance of 150cm in 8s . Calculatell i) the work done by man ii) th
Igoryamba

Answer:

a) 600 J

b) 75 W

Explanation:

Force= 400 N, distance = 150 cm = 1.5 m, time= 8s

a) Work is the product of force acting on an object and distance (or displacement). The S.I unit of work is the joules.

Work = force × distance = 400 × 1.5 = 600 J

b) Power is the amount of energy transferred per unit time. It is the ratio of work to time. The S.I unit of power is watt

Power = work/time = 600 / 8 = 75 W

5 0
2 years ago
Which of the following is a physical property of a substance?? A. Combustion B. Corrosion C. Tendency to tarnish D. Solubility
Fofino [41]
A physical property does not change the substance. 

Solubility would be the answer since all of the rest are changing the substance. They all deal with bonds except solubility. 

Answer: D. Solubility

6 0
3 years ago
Read 2 more answers
What is different types of <br> Metal
Slav-nsk [51]

Answer:

copper metal and steel metak

3 0
2 years ago
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Calculate the volume of a 0.200 M KCl solution containing 5.00 10-2 mol of solute. Enter your answer in the provided box. IL
Paul [167]

Answer:

The volume of a 0.200 M KCl solution containing 5.00 10-2 mol of solute is 0,25 L

Explanation:

Molarity (M) means: moles of solute which are contained in 1 L of solution.  

In this case we have 0,2 moles which are in 1 L, so, as we have 5x10*-2 moles we have to apply a rule of three to find out the volume.

0,2 moles ........... 1 L

5x10*-2 moles ........... x

x= (5x10*-2 moles . 1 L) / 0,2 moles = 0.25L

(we can also say 250 mL)

4 0
3 years ago
A rigid, 2.50 L bottle contains 0.458 mol He. The pressure of the gas inside the bottle is 1.83 atm. If 0.713 mol Ar is added to
Alex17521 [72]

137 K

The volume is constant, so you can use <em>Gay-Lussac’s Pressure-Temperature Law </em>to calculate the new temperature (you don’t have to use the number of moles).

P1/T1 = P2/T2

Solve for T2: T2= T1 x P2/P1

P1 = 1.83 atm; T1 = 122 K

P2 = 2.05 atm; T2 = ?

∴ T2 = 122 K x (2.05 atm)/(1.83 atm) = 137 K

This result makes sense. Temperature is directly proportional to pressure. You increased the pressure by about 10 %, so the temperature increased by about 10 %.

3 0
3 years ago
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