Answer:
Explanation:
To know the temperature at which KCl dissolves in water we need to refer to the general solubility curves.
In the case of , of it will dissolve in of water at a minimum temperature of .
So, the the minimum temperature needed to dissolve 35 grams of KCl in 100 grams of water is .
We need to use the following formula
Δ
n= 4 moles
F= constant= 96500C/mol
let's plug in the values.
ΔG= -(4)(96500)(0.24)=
-92640 J or -92.6 kJ
Explanation:
Answer
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The rule used here is that the algebraic sum of the oxidation numbers of all the atoms a molecule is zero.
Al2O32× ( oxidation number of Al)+3× ( Oxidation number of O ) = 0
2× ( Oxidation number of Al) +3(−2)=0
2× ( oxidation number of Al) +6
∴ Oxidation number of Al =+3
Answer:
3 moles
Explanation:
3 moles atoms are needed to react with 50 grams of O2 gas.
<u>Given:</u>
STP (initial) conditions where: P1 = 1 atm and T1 = 298 K
Volume of gas V1 = 310 cm3
Final conditions:
P1 = 2.1 atm
T2 = 2200 + 273 = 2473 K
<u>To determine:</u>
The final volume (V2) occupied by the gas
<u>Explanation:</u>
Using the combined gas law relation:-
P1V1/T1 = P2V2/T2
V2 = (P1V1/T1)(T2/P2)
= (1*310/298)(2473/2.1) = 1225 cm3
Ans: The volume occupied by the gas under uncontrolled explosion is 1225 cm3