It's hard to tell how the choices are laid out, and they have no labels.
The parallel circuits are the two circuits in your second picture.
One of them is the one with 3 switches, 2 batteries, and 2 light bulbs.
The other one is in the same picture. It's the one where all the circuit components ... the battery and 3 resistors ... are in the 4 vertical lines.
Answer:
<em>1.49 x </em>
<em></em>
<em></em>
Explanation:
Kepler's third law states that <em>The square of the orbital period of a planet is directly proportional to the cube of its orbit.</em>
Mathematically, this can be stated as
∝ 
<em>to remove the proportionality sign we introduce a constant</em>
= k
k = 
Where T is the orbital period,
and R is the orbit around the sun.
For mars,
T = 687 days
R = 2.279 x
for mars, constant k will be
k = 
= 3.987 x 
For Earth, orbital period T is 365 days, therefore
= 3.987 x x
= 3.34 x 
R =<em> 1.49 x </em><em></em>
Answer:
<em>Hello, The velocity of the ball is 0.92 m/s in the downward direction (-0.92 m/s).</em>
Explanation:
The equation for the velocity of an object thrown upward is the following:
v = v0 + g · t
Where:
v = velocity of the ball.
v0 = initial velocity.
g = acceleration due to gravity (-9.8 m/s² considering the upward direction as positive).
t = time.
To find the velocity of the ball at t = 0.40 s, we have to replace "t" by 0.40 s in the equation:
v = v0 + g · t
v = 3.0 m/s - 9.8 m/s² · 0.40 s
v = -0.92 m/s
The velocity of the ball is 0.92 m/s in the downward direction (-0.92 m/s).
<em>Hope That Helps!</em>
Answer: Option A
Explanation:
Acceleration is defined as the rate of change of the vellocity.
Then, if the acceleration is equal zero, the object has a constant velocity or a velocity equal to zero (also constant, of course)
Then, te correct option would be option A; resting, because an object resting has instantaneuos acceleration of zero.
Answer:
Change in electric potential energy is -28.0 J
Explanation:
Electric potential energy is defined as the work is done to move a charge particle from one position to another in space in the presence of other charge particle or electric potential.
OR
Electric potential energy is also equal to the change in the configuration of the charge particles.
Thus,
Change in electric potential energy = - Work Done
According to the problem, Work Done is equal to 28 J. Thus,
Change in electric potential energy = -28 J
