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RSB [31]
3 years ago
15

If a man has brown eye with the recessive gene for blue eyes (Bb), each of his sex cells will have

Chemistry
2 answers:
iren [92.7K]3 years ago
8 0
B - brown eyes
b - blue eyes

If we were to fill out a punette square each of his sex cells would contain at least one brown eyed gene. 
Genrish500 [490]3 years ago
7 0

one gene or the other, B or b that is the answer for study island


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The normal boiling point of chloroform, which has a higher vapor pressure than water at 100 c, is ____.
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Calculate the partial pressure of each gas and the total pressure if the temperature of the gas is 21 ∘C∘C. Express the pressure
Volgvan

The question is incomplete, complete question is ;

A deep-sea diver uses a gas cylinder with a volume of 10.0 L and a content of 51.8 g of O_2 and 33.1 g of He. Calculate the partial pressure of each gas and the total pressure if the temperature of the gas is 21°C.Express the pressures in atmospheres to three significant digits separated by commas.

Answer:

Partial pressure of the oxygen gas is 3.91 atm.

Partial pressure of the helium gas is 20.0 atm

Total pressure of the gases is 24.0 atm

Explanation:

Moles of oxygen gas = n_1=\frac{51.8}{32 g/mol}=1.619 mol

Moles of helium gas = n_2=\frac{33.1 g}{4 g/mol}=8.275 mol

Total moles of gas = n_1+n_2=(1.619 +8.275 ) mole=9.894 mol

Volume of the cylinder = V = 10.0 L

Total pressure in the cylinder = P = ?

Temperature of the gas in cylinder = T = 21°C = 21 + 273 K = 294 K

PV = nRT ( ideal gas equation )

P=\frac{nRT}{V}

=\frac{9.894 mol\times 0.0821 atm L/mol K\times 294 K}{10.0 L}

P = 23.88 atm ≈ 23.9

Partial pressure of the individual gas will be determined by the help of Dalton's law:

partial pressure = Total pressure × mole fraction of gas

Partial pressure of the oxygen gas

p_{1}=P\times \chi_{1}=P\times \frac{n_1}{n_1+n_2}

p_1=23.88 atm\times \frac{1.619 mol}{9.894 mol}=3.91 atm

Partial pressure of the helium gas

p_{2}=P\times \chi_{2}=P\times \frac{n_2}{n_1+n_2}

p_2=23.88 atm\times \frac{8.275 mol}{9.894 mol}=19.97 atm\approx 20.0 atm

6 0
3 years ago
If 25.0 mL of a 2.00 M CaCl2 solution is used for the reaction
RideAnS [48]

0.1 moles of chloride ions were involved  in the reaction if 25.0 mL of a 2.00 M CaCl2 solution is used for the reaction.

Explanation:

Data given:

volume of CaCl_{2} = 25 ml 0r 0.025

molarity of the calcium chloride solution = 2M

number of chloride ions =?

Balance chemical reaction:

Ca + 2Cl_{2} ⇒Ca_{} Cl_{2}

number of moles in 25 ml is calculated as:

molarity = \frac{number of moles}{volume}

number of moles of calcium chloride  = molarity x volume

putting the values in the equation:

number of moles = 2 x 0.025

                            = 0.05 moles of calcium chloride

1 mole of  CaCl_{2}  decomposes as 1 calcium ion and 2 chloride ions

so 0.05 moles will have x moles of chloride ion

\frac{2}{1} = \frac{x}{0.05}

x= 0.1

0.1 moles of chloride ions will be involved in the reaction.

5 0
2 years ago
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