Name 3 objects found in the Milky Way galaxy.

Why might people add a base to an acidic lake?

spayn [35]

Answer:

To decrease the algae

Explanation:

Acid lakes have more algae than other lakes

6 0

2 years ago

HELP PLEASE I WILL GIVE 100 PONTS

pochemuha

Answer:

boiling point

Explanation:

5 0

3 years ago

Read 2 more answers

Extend the aufbau sequence through an element that has not yet been identified, but whose atoms would completely fill 7p orbital

Thepotemich [5.8K]

Answer:

Number of electrons = 118

Electronic configuration: [Rn] 5f¹⁴ 6d¹⁰ 7s² 7p⁶

Explanation:

Given: A chemical element that has completely filled 7p orbital.

According to this, the principal occupied electron shell or the valence shell of such an element is 7p.

⇒ the principal quantum number (n) for the valence shell is 7.

∴ this element belongs to the period 7 of the periodic table.

Also, an element that has completely filled p-orbital belongs to the group 18 of the p-block.

Therefore, an element that belongs to the group 7 and period 18 of the periodic table, should have a completely filled 5f, 6d, 7s and 7p orbitals.

Therefore, the electronic configuration should be: [Rn] 5f¹⁴ 6d¹⁰ 7s² 7p⁶

And, the number of electrons = atomic number of radon (Rn) + 14 + 10 + 2 + 6 = 86 + 32 = 118.

Therefore, the given element has atomic number 118 and has the electronic configuration: [Rn] 5f¹⁴ 6d¹⁰ 7s² 7p⁶. Thus the given element can be Oganesson.

7 0

3 years ago

Tell how many moles of each element are in the following amounts of each compound

qwelly [4]

Take note of the subscript written for each element in the compound. To find the total number of moles, make sure to multiply the subscript with the number of moles of compound. The answer for each is written below:

a. 3*1 = 3 moles Nitrogen; 3*3 = 9 moles Hydrogen
b. 0.25*2 = 0.5 moles Hydrogen; 0.25*1 = 0.25 moles Oxygen
c. 5*2 = 10 moles Hydrogen; 5*1 =5 moles Sulfur; 5*4 = 20 moles Oxygen
d. 0.75*1 = 0.75 moles Calcium; 0.75*1*2 = 1.5 moles Nitrogen; 0.75*3*2 = 4.5 moles Oxygen

7 0

3 years ago

Calculate the mass of ammonia (NH3) that contains a billion (1.00 * 10^12) hydrogen atoms.

Lynna [10]

Answer:

The mass of ammonia (NH3) that contains $1.00 \times 10^12$ hydrogen atoms is $9.4\times 10^{-12}$ g.

Explanation:

As $6.022\times 10^{23}$ atoms of hydrogen = 1 mole of the hydrogen atom

Therefore, $10^{12}$ atoms of hydrogen $= \frac{1}{6.022 \times 10^{23}}\times 10^{12}=1.66\times 10^{-12}$ moles of the hydrogen atom.

Now, there are 3 moles of hydrogen atoms in 1 mole of ammonia $(NH_3)$ .

As the mass of 1 mole of ammonia is 17g, so

when there are 3 moles of hydrogen atoms, then the mass of ammonia = 17 g

Therefore, when there are $1.66\times 10^{-12}$ moles of hydrogen atoms, then the mass of ammonia $= \frac{17}{3}\times 1.66\times 10^{-12}=9.4\times 10^{-12$ g.

Hence, the mass of ammonia $(NH_3)$ that contains $1.00 \times 10^12$ hydrogen atoms is $9.4\times 10^{-12}$ g.

3 0

3 years ago