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IRISSAK [1]
3 years ago
7

Match each of the following terms with the correct definition. Question 6 options: the variable that is measured as data in an e

xperiment the variables that are held constant in an experiment the variable that is changed by the experimenter a count or measurement recorded during an experiment descriptions or observations during an experiment 1. dependent variable 2. controlled variable 3. qualitative data 4. quantitative data 5. independent variable
Chemistry
2 answers:
Aleksandr [31]3 years ago
5 0

The variable that is measured as data in an experiment is 1. the dependent variable.

The variables that are held constant in an experiment are 2. the controlled variables.

The variable that is changed by the experimenter is 5. the independent variable.

A count or measurement recorded during an experiment is 4. quantitative data.

Descriptions or observations during an experiment are 3. qualitative data.

FromTheMoon [43]3 years ago
3 0

Answer:

The answers are explained below.

Explanation:

The dependent variable is defined as the variable that is measured as data in an experiment.

The controlled variables are held constant in an experiment.

Qualitative data are the descriptions or observations during an experiment.

Quantitative data refers to the count or measurement recorded during an experiment.

The independent variable is changed by the experimenter.

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A chemical might be used to melt ice if it raises the temperature of the ice. This best type reaction to accomplish this would b
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The vapor pressure of water at 65oC is 187.54 mmHg. What is the vapor pressure of a ethylene glycol (CH2(OH)CH2(OH)) solution ma
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173.83 mmHg is the vapor pressure of a ethylene glycol solution.

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Vapor pressure of water at 65 °C=p_o= 187.54 mmHg

Vapor pressure of the solution at 65 °C= p_s

The relative lowering of vapor pressure of solution in which non volatile solute is dissolved is equal to mole fraction of solute in the solution.

Mass of ethylene glycol = 22.37 g

Mass of water in a solution = 82.21 g

Moles of water=n_1=\frac{82.21 g}{18 g/mol}=4.5672 mol

Moles of ethylene glycol=n_2=\frac{22.37 g}{62.07 g/mol}=0.3603 mol

\frac{p_o-p_s}{p_o}=\frac{n_2}{n_1+n_2}

\frac{187.54 mmHg-p_s}{187.54 mmHg}=\frac{0.3603 mol}{0.3603 mol+4.5672 mol}

p_s=173.83 mmHg

173.83 mmHg is the vapor pressure of a ethylene glycol solution.

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