The net ionic equation is
Ag⁺(aq) +Cl⁻(aq) → AgCl(s)
Explanation
AgNO₃ (aq) + KCl (aq)→ AgCl(s) +KNO₃(aq)
from above molecular equation break all soluble electrolyte into ions
Ag⁺(aq) +NO₃⁻ (aq) + K⁺(aq) +Cl⁻(aq) → AgCl (s) + K⁺(aq) + No₃⁻(aq)
cancel the spectator ions in both side of equation =K⁺ and NO₃⁻ ions
The net ionic equation is therefore
= Ag⁺(aq) + Cl⁻(aq) → AgCl(s)
Answer:
136 g Al₂O₃
Explanation:
Assuming you do not need to find the limiting reactant, to find the mass of Al₂O₃, you need to (1) convert grams O₂ to moles O₂ (via molar mass), then (2) convert moles O₂ to moles Al₂O₃ (via mole-to-mole ratio from equation coefficients), and then (3) convert moles Al₂O₃ to grams Al₂O₃ (via molar mass). It is important to arrange the conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the sig figs of the given value (64.0 g).
Molar Mass (O₂): 32 g/mol
Molar Mass (Al₂O₃): 102 g/mol
4 Al + 3 O₂ -----> 2 Al₂O₃
64.0 g O₂ 1 mole 2 moles Al₂O₃ 102 g
----------------- x -------------- x ------------------------ x ------------- = 136 g Al₂O₃
32 g 3 moles O₂ 1 mole
Answer:
Mass = 16.4 g
Explanation:
Given data:
Mass of K = 8.50 g
Mass of KCl produced = ?
Solution:
Chemical equation:
2K + Cl₂ → 2KCl
Number of moles of K:
Number of moles = mass/ molar mass
Number of moles = 8.50 g/ 39 g/mol
Number of moles = 0.22 mol
Now we will compare the moles of potassium and potassium chloride.
K : KCl
2 : 2
0.22 : 0.22
Mass of KCl:
Mass = number of moles × molar mass
Mass = 0.22 mol × 74.55 g/mol
Mass = 16.4 g
Answer:
Find the mass of 1 mole.
mass of
1
mole of
131.39
g
m
o
l
C
2
H
C
I
⋅
3
=
37.04000067
g
Explanation:
hope it helps make brainlliest ty
probably none becuase it going staright unless its going down a hill
