A car slows down from 65 km/s to 30 km/s in 5 seconds. What is its acceleration?
1 answer:
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We begin by noting that the angle of incidence is the one that's taken with respect to the normal to the surface in question. In this case the angle of incidence is 30. The material is Flint Glass according to the original question. The refractive indez of air n1=1, the refractive index of red in flint glass is nred=1.57, finally for violet in the glass medium is nviolet=1.60. Snell's Law dictates:
Where
differs for each wavelenght, that means violet and red will have different refractive indices in the glass.
In the second figure provided details are given on which are the angles in question,
is the distance between both rays.
At what distance d from the incidence normal will the beams land at the bottom?
For violet we have:
For red we have:
We finally have:
Where
In the second figure provided details are given on which are the angles in question,
At what distance d from the incidence normal will the beams land at the bottom?
For violet we have:
For red we have:
We finally have:
Answer:
The gauge pressure is
Explanation:
From the question we are told that
The height of the water contained is
The height of liquid in the cylinder is
At the bottom of the cylinder the gauge pressure is mathematically represented as
Where is the pressure of water which is mathematically represented as
Now is the density of water with a constant values of
substituting values
While is the pressure of oil which is mathematically represented as
Where is the density of oil with a constant value
substituting values
Therefore
Answer:
(a) Heat transfer to the environment is: 1 MJ and (b) The efficiency of the engine is: 41.5%
Explanation:
Using the formula that relate heat and work from the thermodynamic theory as: solving to Q_out we get:
this is the heat out of the cycle or engine, so it will be heat transfer to the environment. The thermal efficiency of a Carnot cycle gives us:
where T_Low is the lowest cycle temperature and T_High the highest, we need to remember that a Carnot cycle depends only on the absolute temperatures, if you remember the convertion of K=°C+273.15 so T_Low=150+273.15=423.15 K and T_High=450+273.15=723.15K and replacing the values in the equation we get: