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2 answers:
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Answer:
the position of the wood below the interface of the two liquids is 2.39 cm.
Explanation:
Given;
density of oil, = 926 kg/m³
density of the wood, = 974 kg/m³
density of water, = 1000 kg/m³
height of the wood, h = 3.69 cm
Based on the density of the wood, it will position across the two liquids.
let the position of the wood below the interface of the two liquids = x
Let the wood be in equilibrium position;
Therefore, the position of the wood below the interface of the two liquids is 2.39 cm.
1) 5 N
The crate is initially moving, so we must calculate the force of kinetic friction, which is given by:
where
is the coefficient of friction between the crate (made of wood) and the floor (made of wood). The coefficient of kinetic friction between wood and wood is about 0.2.
is the weight of the crate
Substituting the numbers into the formula, we find
2) 5 N
There are two forces acting on the crate along the horizontal direction:
- The force that pushes the crate toward the right, of magnitude
- The force of friction, which acts in the opposite direction (so, towards the left), of magnitude
Since the two forces are in opposite directions, the net force is given by their difference:
3) Yes
The crate is accelerating. In fact, according to Second Newton's Law:
(1)
where Fnet is the net force on the crate, m is its mass, a is its acceleration. We can immediately see that since Fnet is not zero, the acceleration is also non-zero, so the crate is accelerating.
We can even calculate the magnitude of the acceleration. In fact, the mass of the crate is given by:
And by using (1) we find