2. Connect concepts on the left with a description on the right.

Charge q is 1 unit of distance away from the source charge S. Charge p is two times further away. The force exerted between S an

insens350 [35]

Answer : The correct option is, (d) 4 times

Solution :

According to the Coulomb's law, the electrostatic force of attraction or repulsion between two charges is directly proportional to the product of the charges and is inversely proportional to the square of the distance between the the charges.

Formula used :

$F=k_e\frac{q_1q_2}{r^2}$

where,

F = electrostatic force of attraction or repulsion

$k_e$ = Coulomb's constant

$q_1$ and $q_2$ are the charges

r = distance between two charges

First we have to calculate the force exerted between S and q when the distance between the charge is 1 unit and let us assumed that the charge be 'q'

$F_{sq}=k_e\frac{qq}{1^2}=k_e\times q^2$ ..........(1)

Now we have to calculate the force exerted between S and p when the distance between the charge is 2 unit at the same charge.

$F_{sp}=k_e\frac{qq}{2^2}=k_e\frac{q^2}{4}$ ...........(2)

Equation equation 1 and 2, we get

$\frac{F_{sq}}{F_{sp}}=\frac{1}{4}$

$F_{sq}=4\times F_{sp}$

Therefore, the force exerted between S and q is 4 times the force exerted between S and p.

5 0

2 years ago

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An object of mass m is initially at rest. After a force of magnitude F acts on it for a time T, the object has a speed v. Suppos

adell [148]

Answer:

It takes $\frac{1}{2}T$ to accelerate the object from rest to the speed v.

Explanation:

From Newton's second law:

$F=m\cdot a$ (1)

and the definition of acceleration,

$\displaystyle{a = \frac{\Delta v}{\Delta t}}$ (2)

we can solve this problem. Putting (2) in (1) we have:

$\displaystyle{F = m\cdot \frac{\Delta v}{\Delta t}}$ and solving for $\Delta t$ and considering the initial time as zero ( $t_0=0$ ) and the initial velocity also zero ( $v_0=0$ ) we have:

$\displaystyle{T=\frac{mv}{F}}$

Now, for a mass $m^*= 2m$ and the $F^*=4F$ we can wrtie the same equation:

$\displaystyle{T^*=\frac{m^*v}{F^*}}$ and substituting $m^*$ and $F^*$ :

$\displaystyle{T^*=\frac{2m\cdotv}{4F}=\frac{2}{4}T=\boxed{\frac{1}{2}T}}$

So now, it only takes half the time to accelerate the object from rest to the speed v

5 0

2 years ago

Regions around the nucleus where electrons are most likely to be found are called

ryzh [129]

Answer:

orbitals

Explanation:

The region where an electron is most likely to be is called an orbital. Each orbital can have at most two electrons. Some orbitals, called S orbitals, are shaped like spheres, with the nucleus in the center.

3 0

2 years ago

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What’s Chemical energy

AVprozaik [17]

Answer:

Chemical energy is energy that chemical substance to undergoes a chemical reaction to make a new substance.

Explanation:

<h3>hope this makes sense and helps</h3>

5 0

3 years ago

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If a FM radio station broadcasts at 80. 3 MHz (megahertz), what is its wavelength in m (speed of light 3. 0 x 108 m/s)

hammer [34]

Answer:

Wavelength = 3.74 m

Explanation:

In order to find wavelength in "metres", we must first convert megahertz to hertz.

1 MHz = 1 × 10⁶ Hz

80.3 Mhz = <em>x</em>

<em>x </em>= 80.3 × 1 × 10⁶ = 8.03 × 10⁷ Hz

The formula between wave speed, frequency and wavelength is:

v = fλ [where v is wave speed, f is frequency and λ is wavelength]

Reorganise the equation and make λ the subject.

λ = v ÷ f

λ = (3 × 10⁸) ÷ (8.03 × 10⁷)

λ = 3.74 m [rounded to 3 significant figures]

8 0

2 years ago