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Varvara68 [4.7K]
3 years ago
9

How many molecules of HCI would react with 1 mol of MgO? ​

Chemistry
1 answer:
olganol [36]3 years ago
4 0

Answer:

C.

Explanation:

MoleculesHcl = (1 molMgO/1)(2molHCL/1molMGO)(6.02x10^23/1molHCL) = 1.204x10^24

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A chemical engineer must report the average volume of a certain pollutant produced by the plants under her supervision. Here are
AfilCa [17]

Answer:

The chemical engineer should report average volume of 15.34 L.

Explanation:

Volume of Macon = 0.519 L

Volume of Allegheny = 44.67 L

Volume of Doheny = 0.826 L

Average of the volume of the pollutants:

\frac{0.519 L+44.67 L+ 0.826L}{3}=\frac{46.015 L}{3}=15.33833 L

The rule apply for the addition and subtraction is :

The least precise number present after the decimal point determines the number of significant figures in the answer.

Here the 44.67  has two significant digit after decimal point.So the answer will be reported as in with 2 significant figures after decimal point.

15.33833 L\approx 15.34 L

The chemical engineer should report average volume of 15.34 L.

5 0
3 years ago
What is the mass of 2.30 ×1022 molecules of NaOH (Molar mass = 40.0 g/mol)?
aleksandrvk [35]

Answer:

1.52 g NaOH

Explanation:

The molar mass M is a physical property defined as the mass of a given substance (chemical element or chemical compound) divided by the amount of substance.

Molar mass of NaOH is 40.0 g/mol

40.0 g/mol contains 6.022 × 10²³ molecules

∴ 2.30 × 10²² molecules will contain (2.30 × 10²²) * (40.0)/6.022× 10²³

                                                             = 1.52 g NaOH

6 0
3 years ago
Which occurs when a warm fluid cools down?
amid [387]

Answer:

option A is correct answer of this question

hope it helps and your day will be full of happiness

5 0
3 years ago
Read 2 more answers
A balloon at 32 °C is filled with 21 L of air. What would its volume be at a temperature of 52 °C, assuming pressure remains con
I am Lyosha [343]

Answer:C). 24L

Explanation: it works

4 0
4 years ago
Joan’s initial nickel (II) chloride sample was green and weighed 4.3872 g. After the dehydration reaction and removal of excess
ANEK [815]

Answer:

a) yes, it was an hydrate

b) the number of waters of hydration, x = 6

Explanation:

a) yes it was an hydrate because the mass decreased after the process of dehydration which means removal of water thus some water molecules were present in the sample.

b) NiCl2. xH2O

mass if dehydrated NiCl2 = 2.3921 grams

mass of water in the hydrated sample = mass of hydrated - mass of dehydrated = 4.3872 - 2.3921 = 1.9951 g which represent the mass of water that was present in the hydrated sample.

NiCl2.xH2O

mole of dehydrated NiCl2 = m/Mm = 2.3921/129.5994 = 0.01846 mole

mole of water = m/Mm = 1.9951/18.02 = 0.11072 mole

Divide both by the smallest number of mole (which is for NiCl2) to find the coefficient of each

for NiCl2 = 0.01846/0.01846 = 1

for H2O = 0.11072/0.01846 = 5.9976 = 6

thus the hydrated sample was NiCl2. 6H2O

4 0
3 years ago
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