The pH of blood is 7.35. It is maintained in part by the buffer system composed of carbonic acid (H2CO3) and the bicarbonate (hy
1 answer:
Answer:
b) [bicarbonate]/[carbonic acid] = 9.4
Explanation:
The pH of a buffer system is given by the Henderson-Hasselbach equation:
- pH = pKa + log ([bicarbonate] / [carbonic acid])
Where pka = -log (Ka) = -log(4.2x10⁻⁷) = 6.38
Now we <u>solve for [bicarbonate] / [carbonic acid]</u>:
- 7.35 = 6.38 + log ([bicarbonate] / [carbonic acid])
- 0.97 = log ([bicarbonate] / [carbonic acid])
= [bicarbonate] / [carbonic acid]
- [bicarbonate] / [carbonic acid] = 9.33 ≈ 9.4
So the answer is b).
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Answer:
Mole percent of water in azeotrope is 69%
Explanation:
Clearly, the azeotrope consists of water and perchloric acid.
So, 72% perchloric acid by mass means 100 g of azeotrope contains 72 g of perchloric acid and 28 g of water.
Molar mass of water = 18.02 g/mol and molar mass of perchloric acid = 100.46 g/mol
So, 72 g of perchloric acid = of perchloric acid = 0.72 mol of perchloric acid
Also, 28 g of water = of water = 1.6 mol of water
Hence total number of mol in azeotrope = (1.6+0.72) mol = 2.32 mol of azeotrope
So, mole percent of water in azeotrope = [(moles of water)/(total no of moles)]%
Mole percent of water = % = 69%
Answer:work function= 8.2×10-19J
Minimum wavelength of light required= 2.4×10-7m
Explanation:
The wavelength of incident light was given as 193nm. We have to convert this to meters and have 193×10-9m. Then we use it to find the energy of incident photon E. When E is found we now apply Einstein photoelectric equation to obtain the work function Wo since the kinetic energy of photoelectrons is known as 1.8×10-19J.
From this work function. We can obtain the minimum wavelength of light required. All these steps are shown in the image attached.
