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JulijaS [17]
3 years ago
10

According to VSEPR theory, a molecule with the general formula AX2E2 (A is the central atom, X is the bonded atom and E is a lon

e pair of electrons) has how many regions of electron density around the central atom [ Select ]
Chemistry
1 answer:
ratelena [41]3 years ago
4 0

Answer:

see explanation

Explanation:

An AX₂E₂ geometry is derived from an AX₄ parent geometry and is based upon 4 regions of electron density about the central element and defines a tetrahedral geometry and the geometry is bent angular.

An example is the water molecule (H₂O) with two covalent O - H bonds and two free pair electrons on the central oxygen element.

You might be interested in
What is the mass of oxygen in 300 grams of carbonic acid (H2CO3)
DENIUS [597]

mass of carbonic acid = 300g

molar mass of H2CO3 = 2H + C + 3 O

= 2 x 1.008+ 12.01 + 3 x  16

= 62.03g/mol


moles of H2CO3 = mass/Molar mass

= 300/62.03

= 4.8364 moles


1 mole H2CO3 has 3 moles Oxygen


4.8364 moles H2CO3 contains  

=   3 x 4.8364  moles Oxygen  =   14.509 moles Oxygen


moles = mass/Molar mass


mass of oxygen = moles x Molar mass of Oxygen

= 14.509 x 16

= 232.15g Oxygen

mass of oxygen in 300g of carbonic acid(H2CO3) = 232.15g

7 0
3 years ago
A sample of limestone (calcium carbonate, CaCO3) is heated at 950 K until it is completely converted to calcium oxide (CaO) and
pav-90 [236]

Answer:

Therefore, volume of CO₂ produced in the first step is 9141.404 L

Explanation:

Equations of reactions:

A: CaCO₃(s) ---> CaO(s) + CO₂(g)

B: CaO(l) + H₂O(l) ---> Ca(OH)₂(s)

Molar mass of CaCO₃ = 100 g; molar mass of CaO = 56 g; molar mass of CO₂ = 44 g molar mass of H₂P = 18 g; molar mass of Ca(OH)₂ = 74 g

From equation B, 1 mole of CaO produces 1 mole of Ca(OH)₂

This means that 56 g of CaO produces 74 g of Ca(OH)₂

mass of CaO that produces 8.47 kg or 8470 g of Ca(OH)₂ = 8470 g * 56/74 = 6409.73 g of CaO

Therefore, 6409.73 g of CaO were produced in reaction A

From reaction A, 1 mole of CaCO₃ produces 1 mole CaO and 1 mole of CO₂

Number of moles of CaO in 6409.73 g = 6409.73 g/56 g/mol = 114.46 moles

Therefore, 114.46 moles of CO₂ were produces as well.

Molar volume of gas at STP = 22.4 litres

Volume of CO₂ produced at STP = 114.46 * 22.4 L =2563.904 L

However, the above reaction took place at 950 K and 0.976 atm, therefore volume of CO₂ produced under these conditions are obtained using the general gas equation

Using P₁V₁/T₁ = P₂V₂/T₂

P₁ = 1.0 atm, V₁ = 2563.904 L, T₁ = 273 K, P₂ = 0.976 atm, T₂ = 950 K, V₂ = ?

V₂ = P₁V₁T₂/P₂T₁

V₂ = (1.0 * 2563.904 * 950)/(0.976 * 273)

V₂ = 9141.404 L

Therefore, volume of CO₂ produced in the first step is 9141.404 L

3 0
2 years ago
During a rainy spring, where are you most likely to find surface runoff
Dahasolnce [82]

Answer:On a sloped parking lot

Explanation:

7 0
3 years ago
2.In a titration, 25.00 cm3 of a solution of hydrochloric acid reacted with 18.40 cm3 of sodium hydroxide solution of concentrat
telo118 [61]

Answer:

0.11mol/dm³

Explanation:

The reaction expression is given as:

             HCl   +  NaOH  →  NaCl + H₂O

Volume of acid  = 25cm³  = 0.025dm³

Volume of base  = 18.4cm³ = 0.0184dm³

Concentration of base  = 0.15mol/dm³

Solution:

The concentration of hydrochloric acid = ?

 To solve this problem, let us first find the number of moles of the base;

 Number of moles  = concentration x volume

 Number of moles  = 0.15mol/dm³ x 0.0184dm³  = 0.00276mol

From the balanced reaction equation;

          1 mole of NaOH will combine with 1 mole of HCl

Therefore,  0.00276mol of the base will combine with  0.00276mol of HCl

 So;

  Concentration of acid  = \frac{number of moles }{volume}   = \frac{ 0.00276}{0.025}   = 0.11mol/dm³

4 0
3 years ago
What is the name of B2(SeO4)3
Gnoma [55]

This compound is Boron selenate. Molar mass of B2(SeO4)3 is 450.4948 g/mol.

4 0
3 years ago
Read 2 more answers
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