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JulijaS [17]
3 years ago
10

According to VSEPR theory, a molecule with the general formula AX2E2 (A is the central atom, X is the bonded atom and E is a lon

e pair of electrons) has how many regions of electron density around the central atom [ Select ]
Chemistry
1 answer:
ratelena [41]3 years ago
4 0

Answer:

see explanation

Explanation:

An AX₂E₂ geometry is derived from an AX₄ parent geometry and is based upon 4 regions of electron density about the central element and defines a tetrahedral geometry and the geometry is bent angular.

An example is the water molecule (H₂O) with two covalent O - H bonds and two free pair electrons on the central oxygen element.

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Explain what is going on at the molecular level as your liquid sample cools down and<br> solidifies.
Lemur [1.5K]

Answer:

Freezing. When a liquid is cooled, the average energy of the molecules decreases. At some point, the amount of heat removed is great enough that the attractive forces between molecules draw the molecules close together, and the liquid freezes to a solid.

Note how temperature effects the motion of the atoms or molecules in a liquid. As the temperature of a solid, liquid or gas increases, the particles move more rapidly. As the temperature falls, the particles slow down. If a liquid is cooled sufficiently, it forms a solid.

<h3>I hope it helps you:)</h3>
6 0
2 years ago
Suppose you find a rock that contains some potassium-40 (half-life of 1.3 billion years). you measure the amount and determine t
Alborosie
Equation for Half life :
A = a(0.5)^(t/h)
A is current amount, "a" is initial amount, h is halflife, t is time

5 = 40(0.5)^(t/1.3x10^9)
5/40 = (0.5)^(t/1.3x10^9)
take the log of both sides , power rule
Log(5/40) = (t/1.3x10^9) * Log(0.5)
(1.3x10^9) * Log(5/40) / Log(0.5) = t
3.9x10^9 years = t

And if you think about what a half life is, the time it take for the amount to reduce to half.
40/2 = 20
20/2 = 10
10/2 = 5
It went through 3 half-lifes
3 * 1.3x10^9 = 3.9x10^9 years

7 0
3 years ago
When hydrated copper(II) sulfate crystals are heated, anhydrous copper(II) sulfate forms. A mass of 12.5 g of hydrated copper(II
pychu [463]

The formula of hydrated copper(II) sulfate is CuSO4.10H2O

<h3>What is the formula of the hydrated copper (ii) sulfate salt?</h3>

The formula of the hydrated copper (ii) sulfate is determined as follows:

Mass of hydrated salt = 12.5 g

Mass of anhydrous salt = 8.0 g

Mass of water = 12.5 - 8 = 4.5 g

mole ratio of water and anhydrous salt is;

4.5/18 : 8.0/159.5

0.562 : 0.05

10 : 1

Water of crystallization (n) = 10.

Therefore, the formula of hydrated copper(II) sulfate is CuSO4.10H2O

Learn more about water of crystallization at: brainly.com/question/26146814

#SPJ1

7 0
2 years ago
Determine the molarity for each of these solutions. Then lost the solutions in order of increasing molarity.
Vaselesa [24]
B.) 50g C6H1206 per 0.25L
4 0
4 years ago
400cm³ of dry air was passed over heated copper powder in a hard glass tube until no further change. What volume of remained at
Delicious77 [7]

Explanation:

I think there' will be a decrease in volume of the air.

3 0
3 years ago
Read 2 more answers
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