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3 years ago

Which option is an example of a chemical property?

Chemistry

2 answers:

bulgar [2K]3 years ago

7 0

Reactivity
Hope it helps!

alexandr1967 [171]3 years ago

7 0

Answer: Option (3) is the correct answer.

Explanation:

A property which does not bring any change in the chemical composition of a substance is known as physical property.

For example, shape, size, mass, volume, density, boiling point, melting point etc of a substance are all physical properties.

Whereas a property which changes the chemical composition of a substance is known as chemical property.

For example, precipitation, reactivity, toxicity etc are chemical property.

Thus, we can conclude that out of the given options reactivity is an example of a chemical property.

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Examine the diagram shown. Which are the correct labels for continental plates 1 and 2?

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Answer:

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Explanation:

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2 years ago

I need to know the following above

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IF IT IS HOT AND CONCENTRATED THEN:

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2 years ago

The molecular formula of morphine, a pain-killing narcotic, is c17h19no3. what is the molar mass? what is the mass of 6.02 x 102

kati45 [8]

Molar mass is the mass of one mole of a substance, it can be a chemical element or a compound. It is a characteristic of each pure substance. We calculate it by adding up all of the masses of the atoms involved in the compound. We calculate as follows:
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------------------------------------------------------------
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3 years ago

Consider the following reaction at constant P. Use the information here to determine the value of ΔSsurr at 355 K. Predict wheth

Elena-2011 [213]

Answer:

$\Delta S_{surr} = + 0.32113\: kJ/K$

Explanation:

Given: Entropy of surrounding: ΔSsurr = ?

Temperature: T= 355 K

The change in enthalpy of reaction: ΔH = -114 kJ

Pressure: P = constant

As we know, ΔH = -114 kJ ⇒ negative

Therefore, the given reaction is an exothermic reaction

Therefore, Entropy of surrounding at constant pressure is given by,

$\Delta S_{surr} = \frac{-\Delta H}{T}$

$\therefore \Delta S_{surr} = -\left (\frac{-114 kJ}{355 K} \right ) = + 0.32113\: kJ/K > 0$

In the given reaction:

2NO(g) + O₂(g) → 2NO₂(g)

As, the number of moles of gaseous products is less than the number of moles of gaseous reactants.

$\therefore \Delta S_{system} < 0$

As we know, for a spontaneous process, that the total entropy should be positive.

$\Delta S_{total} = \Delta S_{surr} + \Delta S_{system} > 0$

Therefore, at the given temperature,

if $\Delta S_{surr} > \Delta S_{system} \Rightarrow \Delta S_{total} > 0$ then the given reaction is spontaneous

if $\Delta S_{surr} < \Delta S_{system} \Rightarrow \Delta S_{total} < 0$ then the given reaction is non-spontaneous

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3 years ago

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Vlad1618 [11]

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2 years ago