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max2010maxim [7]
3 years ago
7

How does the suns energy contribute to the movement of water in the water cycle?

Chemistry
1 answer:
Troyanec [42]3 years ago
5 0

Answer:Evaporation

Explanation:

The suns heat speeds the movement of water molecules, until the molecules move fast enough that they jolt out the surface of the water individually. Overtime the water gradually evaporates into water vapor.

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Organize the following elements in order of increasing atomic radius (Ge, He, Sr, O, Ba)
Katen [24]

Answer:

He

O

Ge

Sr

Ba

Explanation:

An atom gets larger as the number of electronic shells increase; therefore the radius of atoms increases as you go down a certain group in the periodic table of elements.

In general, the size of an atom will decrease as you move from left to the right of a certain period.

8 0
3 years ago
Which of the following statements about 13C NMR is not true?A. In 13C proton-decoupled NMR spectra, all peaks are singlets.B. 13
adoni [48]

Answer: .B. 13C NMR spectra display peaks for only carbons that bear hydrogen atoms.

Explanation:

The statements that are true about 13C NMR are:

A. In 13C proton-decoupled NMR spectra, all peaks are singlets.

C 13C NMR chemical shifts occur over a greater range than 1H NMR chemical shifts.

D. 13C NMR easily differentiates between the different hybridized carbons (sp3, sp2, and sp hybridized carbons).organic-chemistry

Therefore, the option that isn't true is option B. "13C NMR spectra display peaks for only carbons that bear hydrogen atoms". This is false because 13C NMR will show every peak in the spectrum and it doesn't matter if it's only carbons that bear hydrogen atoms as everything will be shown.

4 0
3 years ago
In hypothetical element, two energy levels are separated by an energy of 282 kj/mol. what wavelength of light (in nm) is involve
scZoUnD [109]

Answer:

4.23*10^2 nm = 423 nm

Explanation:

E={\frac  {hc}{\lambda }}

h=6.62607015*10^{-34}J*s\\c=299 792 458 m / s\\h*c=1.98644568*10^{-25}J*m

282000 j/mol *1 mol/6*10^(23) = 4.7*10^(-19) J for one electron

\lambda={\frac  {hc}{E }}=\frac{1.98644568*10^{-25}J*m}{4.7*10^{-19}J} =\\\\=4.22648017*10^{-7} m = 4.22648017*10^{-7} m*\frac{10^9 nm}{1 m} =\\\\4.23*10^2 nm = 423 nm

6 0
3 years ago
Aluminum has the electronic configuration 2,8,3. How many valence
Klio2033 [76]

Answer:

3 valence electrons

Explanation:

Because aluminum has three, that means three fluorines can bond. The make the formula AlF3, also known as aluminum trifluoride. Each of the fluorine atoms gets an electron to fill their shell, and the aluminum loses three, giving it a filled shell too (remember, aluminum has three extra electrons).

6 0
3 years ago
To what temperature must a sample of nitrogen at 27°C and 0.625 atm be taken so that it’s pressure becomes 1.125 atm at constant
Karo-lina-s [1.5K]

Answer:

The sample of nitrogen must be taken to 267 ^{0}\textrm{C}.

Explanation:

Let's assume nitrogen gas behaves ideally.

Here amount of nitrogen gas in both states remain constant.

So, in accordance with combined gas law for a given amount of an ideal gas in two different states:            \frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}

where P_{1} and P_{2} are initial and final pressure respectively. V_{1} and V_{2} are initial and final volume respectively. T_{1} and T_{2} are initial and final temperature (in kelvin scale) respectively.

Here V_{1}=V_{2} , P_{1}=0.625atm , T_{1}=(273+27)K=300K and P_{2}=1.125atm

So T_{2}=\frac{P_{2}T_{1}}{P_{1}}=\frac{(1.125atm)\times (300K)}{(0.625atm)}=540K

540 K = (540-273) ^{0}\textrm{C} = 267 ^{0}\textrm{C}

So the sample of nitrogen must be taken to 267 ^{0}\textrm{C}.

8 0
3 years ago
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