Which best describes valence electrons?

Chemistry

2 answers:

jek_recluse [69]3 years ago

8 0

The answer is c the electrons in the outermost orbital

AfilCa [17]3 years ago

4 0

A possibily I’m not 100% sure

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A sample of oxygen gas at a pressure of 1.19 atm and a temperature of 24.4 °C, occupies a volume of 18.7 liters. If the gas is a

mihalych1998 [28]

Answer:

$\boxed {\boxed {\sf 0.757 \ atm}}$

Explanation:

We are asked to find the pressure of a gas given a change in volume. Since the temperature remains constant, we are only concerned with volume and pressure. We will use Boyle's Law, which states the volume is inversely proportional to the pressure. The formula for this law is:

$P_1V_1= P_2V_2$

Initially, the oxygen gas occupies a volume of 18.7 liters at a pressure of 1.19 atmospheres.

$1.19 \ atm * 18.7 \ L = P_2V_2$

The gas expands to a volume of 29.4 liters, but the pressure is unknown.

$1.19 \ atm * 18.7 \ L = P_2 * 29.4 \ L$

We are solving for the new pressure, so we must isolate the variable $P_2$ . It is being multiplied by 29.4 liters. The inverse operation of multiplication is division. Divide both sides of the equation by 29.4 L.

$\frac {1.19 \ atm * 18.7 \ L}{29.4 \ L} =\frac{ P_2 * 29.4 \ L}{29.4 \ L}$

$\frac {1.19 \ atm * 18.7 \ L}{29.4 \ L} =P_2$

The units of liters cancel.

$\frac {1.19 \ atm * 18.7 }{29.4 } =P_2$

$\frac {22.253}{29.4 } \ atm = P_2$

$0.7569047619 \ atm =P_2$

The original measurements all have 3 significant figures, so our answer must have the same. For the number we calculated, that is the thousandth place. The 9 in the ten-thousandth place to the right of this place tells us to round the 6 up to a 7.

$0.757 \ atm \approx P_2$