The specific heat capacity of a substance if 300 j are required to raise the temperature of 207 g by 12 degrees is calculated using the formula below
Q=Mc deltaT
Q(heat required) = 300 j
M(mass) =207g
c(specific heat capacity) = ?
delta t(change in temperature)= 12 c
by making c the subject of the formula
C= Q/ M delta T
C= 300 j/ 267 g x 12 c = 0.0936 j/g/c
Answer:
See attached picture!
Explanation:
There are two types of radioactive decay: alpha and beta.
Alpha decay removes a helium atom from the original element, causing the original mass number to decrease by 4 and the original atomic number to decrease by 2.
Beta decay removes an electron from the original element, causing the original mass number to remain the same and the original atomic number to increase by 1.
To solve your problems, you need to identify which decay is most likely to happen. You could do this by checking the possible answer choices. Usually, professors tell you which decay you are expected to write an equation of, but in this case, it's a matter of trial and error in order to get the answer.
Answer:
In units.
Explanation:
Such as newtons or pounds.
Answer:
The first one is air the second is decreases the third is water the fourth is gas and the last is liquid.
Explanation:
Hope it helps.