0.11 moles of Aluminium chloride
<u>Explanation:</u>
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Given:
2Al + 3Cl₂ → 2AlCl₃
According to the balanced equation:
2 moles pf Aluminium form 2 moles of Aluminium chloride.
So, 1 mole of Al will form 1 mole of Aluminium chloride.
0.11 mole of Al is present.
So, 0.11 mol of Al will form 0.11 mol of Aluminium chloride.
The answer is (3)amine. The aldehyde structure is -CHO. The alcohol structure is -OH. The amine structure is -NH2. And the ether structure is R-O-R'. The "R" means other function groups.
Answer:
HI(aq) + NaOH(aq)-------------> NaI(aq) + H2O(l)
Explanation:
The molecular reaction between hydroiodic acid and aqueous sodium hydroxide is shown above. It is a reaction of one mole of hydroiodic acid with one mole of sodium hydroxide to yield salt and water only. It is a neutralization reaction. Hydrogen iodide dissolves in water to produce hydronium ions which agrees with Arrhenius description of acids. Hydroiodic acid is a strong acid with PKa of -9.3
Conc = moles / Vol you have C but need to find moles
moles KCl = mass / molar mass
25 g / 74.55 g,p;
0.335 moles
So rearrange the formula to find volume. Vol = moles / Conc
0.335 moles / 0.750 mol / L = 0.447 L or 447 mL
The answer in this question is 447 mL.