Answer:
Explanation:
For the growth and flourishing of animals Aromatic amino acids are very important, but because of lack of shikimate these amino acids are not synthesized in animals pathway.But this pathway is found in both plants and micro organisms and they have the ability to produce these amino acids as well as some secondary metabolites required in animals.
There are different role played by this pathway in organisms such as;
1) It serve as a source of Tryptophan and phenylalanie which are important aromatic amino acid.
2)Neuroactive substances such as serotonin,epinephrine are biosynthesized as result of the product from the pathway.
3)Alkaloids that's found in plants as well as antibiotics possessed by microbes, which are essential therapeutical in animals are secondary metabolites that is biosynthesized as a result of the activities of this product of this pathway.
4)Shikimate is useful in the synthesizing of 6-Fluoroshikimic acid.
5) The shikimate pathway is important for the synthesis of a plethora of aromatic compounds in both plants and bacteria as well as fungi.
Answer: 316.8 g CrSO3
Explanation: Solution:
2.4 moles CrSO3 x 132 g CrSO3 / 1 mole CrSO3 = 316.8 g CrSO4
The conversion factor is 1 mole of CrSO4 is equal to its molar mass which is 132 g CrSO3
Answer: the correct option is 2, 3, 4, 1.
Explanation:alphabetic indexing order is the order in which files or names are being arranged according to the alphabet. In the following names:
2) KST Enterprises
3)Leland and Son Graphics
4)Lucinda Topper
1) Topper & Casey Plumbing.
While arranging alphabetically, the first letters are usually considered but in a scenario where alphabet occurs twice( 3 And 4) the second letter is considered. I hope this helps, thanks
Answer:
7650
Explanation:
formula- multiply the volume value by 1e+6
Answer:
g NaCl = 424.623 g
Explanation:
<em>C</em> NaCl = 3.140 m = 3.140 mol NaCl / Kg solvent
∴ solvent: H2O
∴ mass H2O = 2.314 Kg
mol NaCl:
⇒ mol NaCl = (3.140 mol NaCl/Kg H2O)×(2.314 Kg H2O) = 7.266 mol NaCl
∴ mm NaCl = 58.44 g/mol
⇒ g NaCl = (7.266 mol NaCl)×(58.44 g/mol) = 424.623 g NaCl
