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n200080 [17]
2 years ago
6

A solid ball with a mass of 4.25 kg and a

Physics
1 answer:
Liono4ka [1.6K]2 years ago
8 0

7.20 units long yea
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Select all of the answers that apply.
postnew [5]
Here are the answers to the given question above.
<span>Relative dating uses laws or principles of stratigraphy and paleontology. These laws of relative dating are: 
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3 0
3 years ago
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Ben and Dan both weigh 600 N. They are doing pull-ups together. Each pull-up is 0.5 meters of distance. How much work do they ea
Natasha2012 [34]

Answer:

300 J

Explanation:

Work = (Force)*(distance) = 600 N ∗ 0.5 m = 300 J

5 0
2 years ago
9. Know the three types of muscles, their shape, and where they are located.
KatRina [158]
Cardiac, smooth, and skeletal. cardiac muscle cells are located in the walls of the heart and appear striated and are under involuntary control. smooth muscle fibers are located in walls of hollow visceral organs except the heart they also appear striated. skeleton muscle is found between bones and uses tendons to connect to the epimysium to the periosteum, or the outer covering of bone. skeletal muscle is shaped and adapted in many ways.


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8 0
3 years ago
In 1610, galileo used his telescope to discover four prominent moons around jupiter. their mean orbital radii a and periods t ar
katrin2010 [14]

Time period of any moon of Jupiter is given by

T = 2\pi \sqrt{\frac{r^3}{GM}}

from above formula we can say that mass of Jupiter is given by

M = \frac{4 \pi^2 r^3}{GT^2}

now for part a)

r = 4.22 * 10^8 m

T = 1.77 day = 152928 seconds

now by above formula

M = \frac{4 \pi^2 r^3}{GT^2}

M = \frac{4 \pi^2 (4.22 * 10^8)^3}{(6.67 * 10^{-11})(152928)^2}

M = 1.9* 10^{27} kg

Part B)

r = 6.71 * 10^8 m

T = 3.55 day = 306720 seconds

now by above formula

M = \frac{4 \pi^2 r^3}{GT^2}

M = \frac{4 \pi^2 (6.71 * 10^8)^3}{(6.67 * 10^{-11})(306720)^2}

M = 1.9* 10^{27} kg

Part c)

r = 10.7 * 10^8 m

T = 7.16 day = 618624 seconds

now by above formula

M = \frac{4 \pi^2 r^3}{GT^2}

M = \frac{4 \pi^2 (10.7 * 10^8)^3}{(6.67 * 10^{-11})(618624)^2}

M = 1.89* 10^{27} kg

PART D)

r = 18.8 * 10^8 m

T = 16.7 day = 1442880 seconds

now by above formula

M = \frac{4 \pi^2 r^3}{GT^2}

M = \frac{4 \pi^2 (18.8 * 10^8)^3}{(6.67 * 10^{-11})(1442880)^2}

M = 1.889* 10^{27} kg

6 0
3 years ago
If the Earth got closer to the Sun, how would the gravity between the Sun and Earth change?
Neko [114]

Answer:

I think its 2. It would decrease

Explanation:

Hope this helps

4 0
2 years ago
Read 2 more answers
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