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Ronch [10]
3 years ago
10

1. You have 19.7 grams of a material and wonder how many moles were formed. Your

Chemistry
1 answer:
Alex777 [14]3 years ago
5 0

Answer:

No. If you were to set up what the friend said it would look like this:

19.7g × \frac{grams}{moles} ==>  \frac{19.7 grams}{1} ×

The above does not look right because the grams do not cancel out. If it's not cancelled, it would be included in your final answer, but you're looking for moles not grams.

When setting up a stoichiometry equation, you have to put the same unit of measurement (ex- grams, cm, mm, etc.) on the numerator of one side and the denominator of the other side.

This would cancel out the unit.

For example: If you wanted to find out how much of 320 cm are in a meter.

*there are 100 cm in 1 meter*

(1. always start with the given number!)

(2. set up the next fraction where you can cancel out cm)

\frac{320cm}{1} × \frac{1 meter}{100 cm} = 3.2 m

Going back, your friend would have to switch the units from grams/moles to moles/grams. It would cancel out grams, which would leave moles. Therefore, moles will be included in your final answer.

\frac{19.7 grams}{1} × \frac{moles}{grams} = _?_ moles

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Answer:

50mL of 4M NaCl, 80mL of 40% glucose, 20mL of 1M Tris-HCl (pH 8.5) and 250mL of water.

Explanation:

To make 400mL containing 0.5M NaCl you need to add:

4M / 0.5M = 8 (dilution 1/8). 400mL / 8 = <em>50 mL of 4M NaCl.</em>

Glucose 8% you need to add:

40% / 8% = 5 (dilution 1/5). 400mL / 5 = <em>80 mL of 40% glucose </em>

Buffer 50mM you need to add:

1000mM / 50mM = 20 (dilution 1/20). 400mL / 20 = <em>20mL of 1M Tris-HCl (pH 8.5)</em>

<em></em>

The resting volume: 400mL - 50mL of 4M NaCl - 80mL of 40% glucose - 20mL of 1M Tris-HCl (pH 8.5) = 250 mL must be completed with water.

Thus, to make the solution you need: <em>50mL of 4M NaCl, 80mL of 40% glucose, 20mL of 1M Tris-HCl (pH 8.5) and 250mL of water.</em>

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I hope it helps!

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3 years ago
For the reaction PCl5(g) + heat PCl3(g) + Cl2(g), what will happen when the volume is increased?
Fiesta28 [93]
Answer: There will be a shift toward the products. 

The effect of increasing volume will be similar to decreasing pressure, it will shift the equilibrium into the side with higher molecule count. In the reaction above, the product molecule count is 1 (one PCl5) while the product is 2 (one PCl3 + one Cl2). So, increasing volume will increase the rate of product formation.
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Answer:

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0.2756 L

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How many miles of O2 can be produced by letting 12.00 miles of KC103 react?
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