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Ronch [10]
3 years ago
10

1. You have 19.7 grams of a material and wonder how many moles were formed. Your

Chemistry
1 answer:
Alex777 [14]3 years ago
5 0

Answer:

No. If you were to set up what the friend said it would look like this:

19.7g × \frac{grams}{moles} ==>  \frac{19.7 grams}{1} ×

The above does not look right because the grams do not cancel out. If it's not cancelled, it would be included in your final answer, but you're looking for moles not grams.

When setting up a stoichiometry equation, you have to put the same unit of measurement (ex- grams, cm, mm, etc.) on the numerator of one side and the denominator of the other side.

This would cancel out the unit.

For example: If you wanted to find out how much of 320 cm are in a meter.

*there are 100 cm in 1 meter*

(1. always start with the given number!)

(2. set up the next fraction where you can cancel out cm)

\frac{320cm}{1} × \frac{1 meter}{100 cm} = 3.2 m

Going back, your friend would have to switch the units from grams/moles to moles/grams. It would cancel out grams, which would leave moles. Therefore, moles will be included in your final answer.

\frac{19.7 grams}{1} × \frac{moles}{grams} = _?_ moles

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Isaac wants to make s'mores. He holds a marshmallow on a metal skewer over a fire. A few seconds later, the marshmallow is cooke
natita [175]

Answer:

Thermal energy in the form of heat moved from the fire to the skewer and marshmallow.

Explanation:

He holds a marshmallow on a metal skewer over a fire. A few seconds late, the marshmallow is cooked and the skewer feels warm.

8 0
3 years ago
Read 2 more answers
A gas occupies 18.5L at stp. what volume will it occupy at 735 torr and 57°c?
olga nikolaevna [1]

 The volume that  will  be occupied at 735  torr and 57 c  is 23.12 L


 <u><em>calculation</em></u>

  • <u><em> </em></u> At STP   temperature=273 k  and  pressure=760 torr
  • <u><em> </em></u>by use of combined  gas formula

that is P1V1/T1= P2V2/T2

where; P1 =760 torr

           T1= 273  K

           V1= 18.5 L

          P2= 735 torr

         T2=  57+273= 330 K

          V2=?

  • by making   V2 the formula of subject

     V2= T2P1V1/P2T1

       V2=  [(18.5L  x 330 k  x 760 torr)/(735 torr x 273 k)]= 23.12  L




5 0
3 years ago
What is a mol in chemistry
Snowcat [4.5K]
Molecular weight it stands for molecular weight






6 0
3 years ago
If you have 400 grams of a substance that decays with a half-life of 14 days, then how much will you have after 56 days? To help
alisha [4.7K]

Answer:

25 grams

Explanation:

You strat off with 400 grams of your substance. By day 14, half has dcayed and you only have 200 grams left. By day 28, there are 100 grams of the substance. On day 42, there are 50 grams left. Finally, on day 56, the substance has been through four half-lives and 25 grams remain.

3 0
3 years ago
What volume, in milliliters, of a 0.997 M KOH solution is needed to neutralize 30.0 mL of 0.0400 M HCl?
deff fn [24]

Answer:

1.2 mL

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated:

HCl + KOH —> KCl + H₂O

From the balanced equation,

Mole ratio of the acid, HCl (nₐ) = 1

Mole ratio of base, KOH (n₆) = 1

Finally, we shall determine the volume of the base, KOH needed to neutralize the acid, HCl as follow:

Molarity of base, KOH (M₆) = 0.997 M

Volume of acid, HCl (Vₐ) = 30 mL

Molarity of acid, HCl (Mₐ) = 0.0400 M

Volume of base, KOH (V₆) =?

MₐVₐ / M₆V₆ = nₐ/n₆

0.04 × 30 / 0.997 × V₆ = 1/1

1.2 / 0.997 × V₆ = 1

Cross multiply

0.997 × V₆ = 1.2

Divide both side by 0.997

V₆ = 1.2 / 0.997

V₆ = 1.2 mL

Thus, the volume of the base, KOH needed to neutralize the acid is 1.2 mL.

7 0
3 years ago
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