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Leviafan [203]
2 years ago
9

Perform each of the following unit conversions using the conversion factors given below:

Chemistry
2 answers:
lianna [129]2 years ago
7 0

Answer: (what's in bold is the answer! straight off of edge!)

1.429 atm = 1,086 mmHg

9,361 Pa = 9.361

kPa  = 70.21 mmHg

725 mmHg = 0.954

atm = 96.26 ⇒ 96.7 kPa

andrezito [222]2 years ago
4 0

1. 1086.04 mmHg

2.70.213 mmHg

3. 95.954 kPa

<h3>Further explanation</h3>

Pressure (P) is the force applied per unit area

Can be formulated :

\tt P=\dfrac{F}{A}

P = pressure (SI=Pascal(Pa))

F= force applied (N)

A=area(m²)

The unit of pressure can be expressed in atm, mmHg, or Pascal

\tt 1.\dfrac{1.429}{1}\times 760=1086.04~mmHg

\tt 2)~9,361~Pa=9.361~kPa=\dfrac{9.361}{101.325}\times 760=70.213~mmHg

\tt 3)\dfrac{725}{760}\times 1=0.947~atm=\dfrac{0.947}{1}\times 101.325=95.954~kPa

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anzhelika [568]

Answer:

The volume of the water is 108.71 mL

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concentration of sucrose solution 35 % w/w this means in 100 grams of water we have 35 grams of sucrose

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Step 2: Calculate the density of the solution

Density = specific gravity * density of water

Density of solution = 1.115 * 1g/ mL

Density of solution = 1.115 g/ mL

Step 3: Calculate mass of the solution

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Mass of water = mass of sample - mass of sucrose

Mass of water = 167.25 - 58.54 = 108.71 grams

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5 0
3 years ago
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2C4 H10 + 13O2 -→ 8CO2 + 10H2O If 356 moles of O2 are available to react, how many moles of CO2 will fom?
nlexa [21]

Answer:

Answer:

The mole ratio of C₄H₁₀ and CO₂ is 2 : 8, which  simplifies to 1 : 4.

Explanation:

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The chemical equation given is:

2C₄H₁₀ + 13O₂ → 8CO₂ + 10H₂O

Once you check that the equation is balanced, you can set the mole ratios for all the reactants and products. The coefficients used in front of each reactant and product, in the balanced chemical equation, tells the mole ratios.

In this case, they are: 2 mol C₄H₁₀ :  13 mol O₂ : 8 mol CO₂ : 10 mol H₂O

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5 0
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nataly862011 [7]
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7 0
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Which models of the atom include a structure that is mostly made of empty space?RutherfordThomsonBohrQuantum mechanical
Luba_88 [7]
<h2>Answer:</h2>

Rutherford's models

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