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2 years ago

14

Match the variables with quantities

1 answer:

Flauer [41]2 years ago

4 0

23 meters/sec
23 kilograms
23 meters
23 m/s2
23 newtons
23 sec

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Which statement best describes how work and power are different?

WARRIOR [948]

Hello
the best answer is c

6 0

4 years ago

If a driver makes contact with a steering wheel during a 35 mph crash, she comes to rest in about Δ=15 ms. If, during an identic

tatyana61 [14]

Answer:

The ratio of forces is 22 : 3.

Explanation:

Case I:

initial velocity, u = 35 mph

final velocity, v = 0

time, t = 15 ms

Case II:

initial velocity, u = 35 mph

final velocity, v = 0

time, t' = 110 ms

let the mass is m.

According to the Newton's second law, the force is given by the rate of change of momentum.

So

$F =\frac{m(v-u)}{t}\\\\F'= \frac{m(v-u)}{t'}\\\\So, \frac{F}{F'} =\frac{t'}{t}\\\\\frac{F}{F'}=\frac{110}{15}=22:3$

6 0

3 years ago

The force between two charges when they are 2 cm apart is

mixer [17]

Answer:

$q_1=9.9998\mu C$ and $q_2=0.0002\mu C$

Or

$q_1=0.00016\mu C$ and $q_2=9.99984\mu C$

Explanation:

We are given that

Force between two charges=0.036 N= $36\times 10^{-3}N$

Distance between two charges, r=2cm= $2\times 10^{-2}$ m

1m=100cm

Sum of two charges= $10\mu C$

Let one charge= $q_1=q\mu C=q\times 10^{-6}C$

$q_2=(10-q)\times 10^{-6} C$

We know that

Electric force between two charges

$F=\frac{kq_1q_2}{r^2}$

Where $k=\frac{1}{4\pi \epsilon_0}=9\times 10^{9}$

Using the formula

$36\times 10^{-3}=9\times 10^{9}\times \frac{q\times 10^{-6}\times(10-q)\times 10^{-6}}{(2\times 10^{-2})^2}$

$\frac{144\times 10^{-7}}{9\times 10^{9}\times 10^{-12}}=q(10-q)$

$0.0016=10q-q^2$

$q^2-10q+0.0016=0$

$10000q^2-100000q+16=0$

$q=\frac{100000\pm\sqrt{(100000)^2-4\times 10000\times 16}}{2\times 10000}$

Using the formula

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$q=9.999$ and $q=0.00016$

$q_2=10-9.9998=0.0002$

$q_2=10-0.00016=9.99984$

Hence, two charges are

$q_1=9.9998\mu C$ and $q_2=0.0002\mu C$

Or

$q_1=0.00016\mu C$ and $q_2=9.99984\mu C$

5 0

3 years ago

Plzz help.me with both questions

Hatshy [7]

Explanation:

Primary cell

1. They are non-rechargeable.

2. The energy density of primary cells is more.

3. The internal resistance of primary cells is more.

4. Example : Zinc-Carbon cell.

Secondary cells

1. They are rechargeable cells.

2. The energy density of secondary cells is less.

3. The internal resistance of secondary cells is less.

4. Example : Car batteries

Current :

The flow of electric charge per unit time is called electric current. It can be given by the formula as follows :

$I=\dfrac{q}{t}$

The SI unit of electric current is Ampere.

1 Ampere is defined as the current that flows with the electric charge of one Coulomb per second (C/s).

5 0

3 years ago

The volume of 1 kg of helium in a piston-cylinder device is initially 5 m3. Now helium is compressed to 2 m3 while its pressure

yuradex [85]

Answer:

-540 kJ

Explanation:

P = Pressure which is applied to the piston = 180 kPa

$V_2$ = Final volume = 2 m³

$V_1$ = Initial volume = 5 m³

Work done is given by

$W=P\Delta V\\\Rightarrow W=P(V_2-V_1)\\\Rightarrow W=180000(2-5)\\\Rightarrow W=180000\times -3\\\Rightarrow W=-540000\ J\\\Rightarrow W=-540\ kJ$

The work required to compress helium is -540 kJ

4 0

4 years ago