Answer:
The net force acting on an object is proportional to the acceleration of that object with respect to an inertial frame of reference. The constant of proportionality in this, Newton's second law, is the classical mass of the object.
Explanation:
Answer:
602.27 kg
Explanation:
The computation of the largest mass of cargo the balloon can lift is shown below:-
Volume of helium inside the ballon= (4 ÷ 3) × π × r^3
= (4 ÷ 3) × 3.14 × 6.953
= 1406.19 m3
Mass the balloon can carry = volume × (density of air-density of helium)
= 1406.19 × (1.29-0.179)
= 1562.27 kg
Mass of cargo it can carry = Mass it can carry - Mass of structure
= 1562.27 - 960
= 602.27 kg
Answer:
voltage across = 1.6 V
Explanation:
given data
resistance R = 57.61 Ω
capacitance c = 13.13 mF = 13.13 ×
F
inductance L = 196.03 mH = 0.19603 H
fixed rms output Vrms = 23.86 V
to find out
voltage across circuit
solution
we know resonant frequency that is
resonant frequency = 1 / ( 2π√(LC)
put the value
resonant frequency = 1 / ( 2π√(0.19603×13.13 ×
)
resonant frequency f = 3.1370 HZ
so current will be at this resonant is
current = Vrms / R
current = 23.86 / 57.61
current = 0.4141 A
and
so voltage across will be
voltage across = current / ( 2π f C )
voltage across = 0.4141 / ( 2π ( 3.1370) 13.13 ×
)
voltage across = 1.6 V
In order to achieve stable circular gravitational and centrifugal force must be in balance.

This relationship tells closer the closser your orbit is to the surface of the planet the faster you have to go. Which makes sense because the closer you are to the planet the stronger gravitational force gets.
Answer:
A) A humidity level of 90 percent is too high.
Explanation:
A humidity level of 90% is too high . It reflects real or possible situation .
Atmospheric temperature between 20 - 30 degree makes comfortable weather. 70 or 80 or 90 degree atmospheric temperature is impossible to achieve on the earth in normal case. The maximum temperature upto which
atmospheric temperature has gone is 55 degree .
So all the other statements appear to be false.